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[api] Inline APIServer::is_connected() for common no-arg path#14574 - lambda equivalent for state_subscription_only is wrong #6320

@uli-rpi

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@uli-rpi

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The lambda equivalent for state_subscription_only has not been updated in 2026.3.0. dokumentation

id(api_id).is_connected(true) -> id(api_id).is_connected_with_state_subscription()

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https://esphome.io/components/api/#advantages-over-mqtt

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