On using Asyncio

[BhuwanPandey]

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Example Code

Hey there,
I have file abcd.py where code looks like

from asyncio import run as aiorun
import typer

app = typer.Typer()

async def async_process():
    print("hello I am async")

@app.command()
def hello():
    print("I am Hello")


@app.command()
def async_handle():
    aiorun(async_process())

if __name__ == "__main__":
    app()

when I run 
python abcd.py async_handle it run successfully but

but when I changed code to

from asyncio import run as aiorun
import typer

app = typer.Typer()

async def async_process():
    print("hello I am async")


@app.command()
def async_handle():
    aiorun(async_process())

if __name__ == "__main__":
    app()

when i run abcd.py async_handle, it say
Got unexpected extra argument (async-handle)

Description

..

Operating System

Windows

Operating System Details

No response

Typer Version

0.12.3

Python Version

3.11

Additional Context

No response

[YuriiMotov]

This is because if you have only one command, Typer makes some optimizations and you don't need to specify command to call it. So, it treats async_handle in abcd.py async_handle as an argument, thus it shows that error.

The solution is to add a callback as described here: https://typer.tiangolo.com/tutorial/commands/one-or-multiple/#one-command-and-one-callback

from asyncio import run as aiorun
import typer

app = typer.Typer()

async def async_process():
    print("hello I am async")


@app.command()
def async_handle():
    aiorun(async_process())

@app.callback()
def callback():
    pass

if __name__ == "__main__":
    app()

And, your command name will actually be async-handle (with dash instead of underscore).

Try it:

$ python abcd.py async-handle
hello I am async