[firebase_database] Why isn't DataSnapshot.value a Map or dynamic in version: ^9.0.0?

[Michael-Eliosov]

Before, I would access a value like DataSnapshot.value[key], now I have to do DataSnapshot.child(key).value or assign DataSnapshot.value to a variable and then variable[key].

Please tell me I'm missing something

[rrousselGit]

value can be multiple things. It may be a Map, but can also be a String or number, ...

[Michael-Eliosov]

Then why doesn't Map a = DataSnapshot.value raise no error?

[TheHypnoo]

@Michael-Eliosov
Now with the new version ^ 9. does the value return an "Object?" that depending on what you return you can treat it in different ways, such as a Map or primitive values ​​(String, int ..)

In this case the .value does not return the ordered values

[Michael-Eliosov]

@Michael-Eliosov Now with the new version ^ 9. does the value return an "Object?" that depending on what you return you can treat it in different ways, such as a Map or primitive values ​​(String, int ..)

My problem is precisely that I cannot treat it as a Map (it gives an error that Object has no method [] )

[TheHypnoo]

Could you show an example of it?

[Michael-Eliosov]

Sure.

FirebaseDatabase.instance.ref("Users").once().then((data) {
   return data.snapshot.value["user"];
}

Android Studio says:

The operator '[]' isn't defined for the type 'Object'.

Meanwhile, this works fine:

FirebaseDatabase.instance.ref("Users").once().then((data) {
    Map result = data.snapshot.value;
    return result["user"];
  });

[deepak786]

you have to cast the value to map now.

FirebaseDatabase.instance.ref("Users").once().then((data) {
   return (data.snapshot.value as Map)["user"];
}

[Michael-Eliosov]

Thanks, though that's really dumb