Fix #183

Author: terehov

README.md

@@ -274,7 +274,6 @@ firstSubLogger.silly("foo bar 1");
 #### Sub-logger with `LogObj`
 You can also overwrite the `LogObj`(s. below), when you create a sub-logger:
 
-
 ```typescript
 const mainLogObj = { main: true, sub: false };
 const mainLogger = new Logger({ type: "pretty", name: "MainLogger" }, mainLogObj);

docs/README.md

@@ -274,7 +274,6 @@ firstSubLogger.silly("foo bar 1");
 #### Sub-logger with `LogObj`
 You can also overwrite the `LogObj`(s. below), when you create a sub-logger:
 
-
 ```typescript
 const mainLogObj = { main: true, sub: false };
 const mainLogger = new Logger({ type: "pretty", name: "MainLogger" }, mainLogObj);

src/BaseLogger.ts

@@ -28,7 +28,7 @@ export class BaseLogger<LogObj> {
         settings?.prettyLogTemplate ??
         "{{yyyy}}.{{mm}}.{{dd}} {{hh}}:{{MM}}:{{ss}}:{{ms}}\t{{logLevelName}}\t[{{filePathWithLine}}{{nameWithDelimiterPrefix}}]\t",
       prettyErrorTemplate: settings?.prettyErrorTemplate ?? "\n{{errorName}} {{errorMessage}}\nerror stack:\n{{errorStack}}",
-      prettyErrorStackTemplate: settings?.prettyErrorTemplate ?? "  • {{fileName}}\t{{method}}\n\t{{filePathWithLine}}",
+      prettyErrorStackTemplate: settings?.prettyErrorStackTemplate ?? "  • {{fileName}}\t{{method}}\n\t{{filePathWithLine}}",
       prettyErrorParentNamesSeparator: settings?.prettyErrorParentNamesSeparator ?? ":",
       prettyErrorLoggerNameDelimiter: settings?.prettyErrorLoggerNameDelimiter ?? "\t",
       stylePrettyLogs: settings?.stylePrettyLogs ?? true,

src/index.ts

@@ -76,6 +76,7 @@ export class Logger<LogObj> extends BaseLogger<LogObj> {
    *  Returns a child logger based on the current instance with inherited settings
    *
    * @param settings - Overwrite settings inherited from parent logger
+   * @param logObj - Overwrite logObj for sub-logger
    */
   public getSubLogger(settings?: ISettingsParam<LogObj>, logObj?: LogObj): Logger<LogObj> {
     return super.getSubLogger(settings, logObj) as Logger<LogObj>;