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Fix eb4c695
Apply suggestions requested on that commit, which should have been PR'd but was directly committed by mistake
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src/Interrupts.md

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@@ -74,11 +74,11 @@ The following occurs when control is being transferred to an interrupt handler:
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1. Two wait states are executed (2 M-cycles pass while nothing
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occurs, presumably the CPU is executing `nop`s during this time).
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2. The current PC is pushed onto the stack, consuming 2 more M-cycles.
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2. The current PC is pushed to the stack, consuming 2 more M-cycles.
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3. The PC register is set to the address of the handler ($40, $48, $50, $58, $60).
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This consumes one last M-cycle.
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The entire ISR **should** consume a total of 5 M-cycles.
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The entire ISR **should** last a total of 5 M-cycles.
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This has yet to be tested, but is what the Z80 datasheet implies.
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## Interrupt Priorities

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