Merge branch 'geekcomputers:master' into testing

Author: NitkarshChourasia

FIND FACTORIAL OF A NUMBER.py

@@ -1,12 +1,13 @@
 # Python program to find the factorial of a number provided by the user.
 
 def factorial(n):
-	if n < 0:
+	if n < 0:         # factorial of number less than 0 is not possible
 		return "Oops!Factorial Not Possible"
-	elif n == 0:
+	elif n == 0:    # 0! = 1; when n=0 it returns 1 to the function which is calling it previously. 
 		return 1
 	else:
-		return n*factorial(n-1)
+		return n*factorial(n-1)  
+#Recursive function. At every iteration "n" is getting reduced by 1 until the "n" is equal to 0.
 
-n = int(input())
-print(factorial(n))
+n = int(input("Enter a number: ")) # asks the user for input 
+print(factorial(n))    # function call

Hand-Motion-Detection/requirements.txt

@@ -1,3 +1,3 @@
 numpy==1.25.2
-opencv_python==4.8.0.74
+opencv_python==4.8.0.76
 mediapipe==0.10.3

Sum of digits of a number.py

@@ -1,7 +1,13 @@
-q=0
-n=int(input("Enter Number: "))
-while(n>0):
- r=n%10
- q=q+r
- n=n//10
+q=0   # Initially we assigned 0 to "q", to use this variable for the summation purpose below.
+    # The "q" value should be declared before using it(mandatory). And this value can be changed later.
+
+n=int(input("Enter Number: "))   # asking user for input
+while n>0:         # Until "n" is greater than 0, execute the loop. This means that until all the digits of "n" got extracted.
+
+   r=n%10           # Here, we are extracting each digit from "n" starting from one's place to ten's and hundred's... so on.
+
+   q=q+r            # Each extracted number is being added to "q".
+
+   n=n//10          # "n" value is being changed in every iteration. Dividing with 10 gives exact digits in that number, reducing one digit in every iteration from one's place.
+
 print("Sum of digits is: "+str(q))