base_ref_store_init(): remove submodule argument

This is another step towards weakening the 1:1 relationship between
ref_stores and submodules.

Signed-off-by: Michael Haggerty <[email protected]>
Reviewed-by: Jeff King <[email protected]>
Signed-off-by: Junio C Hamano <[email protected]>

Author: mhagger

refs.c

@@ -1477,8 +1477,7 @@ struct ref_store *get_ref_store(const char *submodule)
 }
 
 void base_ref_store_init(struct ref_store *refs,
-			 const struct ref_storage_be *be,
-			 const char *submodule)
+			 const struct ref_storage_be *be)
 {
 	refs->be = be;
 }

refs/files-backend.c

@@ -980,7 +980,7 @@ static struct ref_store *files_ref_store_create(const char *submodule)
 	struct files_ref_store *refs = xcalloc(1, sizeof(*refs));
 	struct ref_store *ref_store = (struct ref_store *)refs;
 
-	base_ref_store_init(ref_store, &refs_be_files, submodule);
+	base_ref_store_init(ref_store, &refs_be_files);
 
 	refs->submodule = submodule ? xstrdup(submodule) : "";
 

refs/refs-internal.h

@@ -632,12 +632,11 @@ struct ref_store {
 };
 
 /*
- * Fill in the generic part of refs for the specified submodule and
- * add it to our collection of reference stores.
+ * Fill in the generic part of refs and add it to our collection of
+ * reference stores.
  */
 void base_ref_store_init(struct ref_store *refs,
-			 const struct ref_storage_be *be,
-			 const char *submodule);
+			 const struct ref_storage_be *be);
 
 /*
  * Return the ref_store instance for the specified submodule. For the