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Wrong answers from integralBinomialPDF for p = 0.0 and p = 1.0 #97

@gaurav-arya

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@gaurav-arya

For example, integralBinomialPDF 3 1 3 = 2.718281828459045. The issue seems to be that the edge-case handling in integralBinomialLogPdf outputs the actual PDF rather than the log PDF:

| p == 0.0 && xI == 0 = 1.0
| p == 0.0 = 0.0
| p == 1.0 && xI == nI = 1.0
| p == 1.0 = 0.0
| xI == 0 = n * log (1-p)
| xI == nI = n * log p
.

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