Carriage return does not work in run-shell-command

[KevinGimbel]

Summary

When running a shell command with run-shell-command which uses carriage return (\r) the lines are printed in one line.

Reproduction Steps

Recording https://asciinema.org/a/Nl9KT1Wk5RH90UGBPIZjGob5H

I tried this:

1. hx
2. :run-shell-command + my script which prints in a loop with \r

I expected this to happen:

• Carriage return (\r) should return the cursor to the beginning of the line and replace the line

Instead, this happened:

• The line was written without carriage return

The same happens with a small bash script

#!/bin/bash

for i in 1 2 3 4 5; do
  printf "\r Iteration $i"
  sleep 1
done

Helix log

~/.cache/helix/helix.log

please provide a copy of `~/.cache/helix/helix.log` here if possible, you may need to redact some of the lines

Platform

macOS

Terminal Emulator

wezterm 20240203-110809,5046fc22

Installation Method

brew

Helix Version

helix 24.7 (079f544)

[RoloEdits]

Helix doesn't have a "shell" that would "interpret" the returns(or anything else), its just displaying the returned output as a string; the raw output is captured and returned after the end of shell execution.

Something basic could probably be done for this specific case, where if \r is not followed by a \n it can truncate as if that was the new start of the string. Done in a loop this would yield only the last result. I'm not sure what kind of functionality you are looking for, but sh is only meant for most simple feedback use cases., not as a shell in itself.

[KevinGimbel]

Thanks! I wasn't looking for anything specific, I just assumed it would use a "real shell" (for lack of better wording).
If this is intended behaviour I'm fine with it.