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units of cool function #5

@randomwraith

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@randomwraith

Are the units returned from the cool function correct?

If thermal conductivity is in W / [ m.K] , surface area in m^2, delta T in K, duration in T (seconds) then cooling power has units

W / [m.K] . m^2 . K / T = W.m / T which is kW m / T after dividing by 1000

Then, with heat capacity in kJ / [kg.K], Joules in W.T and mass in Kg, the subsequent get_deltaT function returns units:

[kW.m / T] . T / [kJ / [kg.K] . Kg] = [kW.m ] / [kJ / [ K] ] = [kW.m ] / [kW.T / [ K] ] = K.m / T

Which is not K!! Unless I'm mistaken I think the duration in this function should in fact be the width or depth of the material, which is consistent Q being a heat flux in W / m^2 and will ensure the cool function returns temperature change in units of temperature.

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