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Time: 0 ms (100%), Space: 17.6 MB (97.65%) - LeetHub
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# Definition for a binary tree node.
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# class TreeNode:
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# def __init__(self, val=0, left=None, right=None):
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# self.val = val
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# self.left = left
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# self.right = right
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# time complexity: O(n)
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# space complexity: O(n)
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class Solution:
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def postorderTraversal(self, root: Optional[TreeNode]) -> List[int]:
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result = []
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def traverse(node):
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if node is None:
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return
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if node.left:
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traverse(node.left)
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if node.right:
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traverse(node.right)
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result.append(node.val)
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return
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traverse(root)
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return result
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