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Remove some stray Ms
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src/IndProp.lidr

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@@ -555,7 +555,7 @@ $\square$
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> namespace R
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>
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==== Exercise: 3 stars, recommendedM (R_provability)
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==== Exercise: 3 stars, recommended (R_provability)
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We can define three-place relations, four-place relations, etc., in just the
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same way as binary relations. For example, consider the following three-place
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$\square$
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==== Exercise: 2 stars, optionalM (R_provability2)
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==== Exercise: 2 stars, optional (R_provability2)
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Suppose we give Idris the following definition:
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src/Logic.lidr

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$\square$
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==== Exercise: 1 star, advancedM (informal_not_PNP)
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==== Exercise: 1 star, advanced (informal_not_PNP)
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Write an informal proof (in English) of the proposition \idr{Not (p, Not p)}.
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src/Poly.lidr

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@@ -121,7 +121,7 @@ an appropriate type parameter:
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> test_repeat2 = Refl
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==== Exercise: 2 starsM (mumble_grumble)
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==== Exercise: 2 stars (mumble_grumble)
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\ \todo[inline]{Explain implicits and \idr{{x=foo}} syntax first? Move after the
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"Supplying Type Arguments Explicitly" section?}
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> zip (x::tx) (y::ty) = (x,y) :: zip tx ty
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==== Exercise: 1 star, optionalM (combine_checks)
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==== Exercise: 1 star, optional (combine_checks)
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Try answering the following questions on paper and checking your answers in
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Idris:
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> fold_example3 = Refl
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==== Exercise: 1 star, advancedM (fold_types_different)
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==== Exercise: 1 star, advanced (fold_types_different)
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Observe that the type of \idr{fold} is parameterized by _two_ type variables,
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\idr{x} and \idr{y}, and the parameter \idr{f} is a binary operator that takes
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$\square$
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==== Exercise: 3 starsM (fold_map)
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==== Exercise: 3 stars (fold_map)
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We can also define \idr{map} in terms of fold. Finish \idr{fold_map} below.
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$\square$
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==== Exercise: 2 stars, advancedM (nth_error_informal)
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==== Exercise: 2 stars, advanced (nth_error_informal)
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Recall the definition of the \idr{nth_error} function:
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src/Tactics.lidr

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@@ -178,7 +178,7 @@ hypotheses in the context. Remember that `:search` is your friend.)
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$\square$
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==== Exercise: 1 star, optionalM (apply_rewrite)
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==== Exercise: 1 star, optional (apply_rewrite)
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Briefly explain the difference between the tactics \idr{exact} and
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\idr{rewriteWith}. What are the situations where both can usefully be applied?
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$\square$
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==== Exercise: 2 stars, advancedM (beq_nat_true_informal)
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==== Exercise: 2 stars, advanced (beq_nat_true_informal)
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Give a careful informal proof of \idr{beq_nat_true}, being as explicit as possible
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about quantifiers.
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$\square$
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==== Exercise: 3 stars, advancedM (split_combine)
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==== Exercise: 3 stars, advanced (split_combine)
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We proved, in an exercise above, that for all lists of pairs, \idr{zip} is the
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inverse of \idr{unzip}. How would you formalize the statement that \idr{unzip}

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