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## What changes were proposed in this pull request?
In the PR, I propose to automatically convert a `Literal` with `Char` type to a `Literal` of `String` type. Currently, the following code:
```scala
val df = Seq("Amsterdam", "San Francisco", "London").toDF("city")
df.where($"city".contains('o')).show(false)
```
fails with the exception:
```
Unsupported literal type class java.lang.Character o
java.lang.RuntimeException: Unsupported literal type class java.lang.Character o
at org.apache.spark.sql.catalyst.expressions.Literal$.apply(literals.scala:78)
```
The PR fixes this issue by converting `char` to `string` of length `1`. I believe it makes sense to does not differentiate `char` and `string(1)` in _a unified, multi-language data platform_ like Spark which supports languages like Python/R.
Author: Maxim Gekk <[email protected]>
Author: Maxim Gekk <[email protected]>
Closesapache#21578 from MaxGekk/support-char-literals.
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