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1 | 1 | package g3401_3500.s3470_permutations_iv; |
2 | 2 |
|
3 | | -// #Hard #2025_03_02_Time_12_ms_(100.00%)_Space_45.94_MB_(100.00%) |
| 3 | +// #Hard #2025_03_02_Time_12_ms_(100.00%)_Space_44.78_MB_(100.00%) |
4 | 4 |
|
5 | 5 | import java.util.ArrayList; |
6 | | -import java.util.Arrays; |
7 | 6 | import java.util.List; |
8 | 7 |
|
9 | | -public class Solution { |
10 | | - // Define a large constant value to cap calculations and prevent overflow |
11 | | - private static final long CAP = 1000000000000001L; |
12 | | - // 3D DP array to store precomputed results for dynamic programming |
13 | | - private static final long[][][] DP = new long[105][105][3]; |
| 8 | +class Solution { |
| 9 | + private static final long INF = 1_000_000_000_000_000_000L; |
14 | 10 |
|
15 | | - // Initialize DP array with -1 (indicating uncomputed states) |
16 | | - static { |
17 | | - for (long[][] longs : DP) { |
18 | | - for (long[] aLong : longs) { |
19 | | - Arrays.fill(aLong, -1); |
| 11 | + private long helper(int a, int b) { |
| 12 | + long res = 1; |
| 13 | + for (int i = 0; i < b; i++) { |
| 14 | + res *= (a - i); |
| 15 | + if (res > INF) { |
| 16 | + return INF; |
20 | 17 | } |
21 | 18 | } |
| 19 | + return res; |
22 | 20 | } |
23 | 21 |
|
24 | | - // Recursive function to count alternating permutations |
25 | | - private long rec(int o, int e, int req) { |
26 | | - if (o == 0 && e == 0) { |
| 22 | + private long solve(int odd, int even, int r, int req) { |
| 23 | + if (r == 0) { |
27 | 24 | return 1; |
28 | 25 | } |
29 | | - if (DP[o][e][req] != -1) { |
30 | | - return DP[o][e][req]; |
31 | | - } |
32 | | - long count = 0; |
33 | | - if (req == 2) { |
34 | | - if (o > 0) { |
35 | | - count = addCapped(count, multiplyCapped(o, rec(o - 1, e, 1))); |
36 | | - } |
37 | | - if (e > 0) { |
38 | | - count = addCapped(count, multiplyCapped(e, rec(o, e - 1, 0))); |
39 | | - } |
40 | | - } else if (req == 0) { |
41 | | - if (o > 0) { |
42 | | - count = multiplyCapped(o, rec(o - 1, e, 1)); |
43 | | - } |
| 26 | + int nodd; |
| 27 | + int neven; |
| 28 | + if (req == 1) { |
| 29 | + nodd = (r + 1) / 2; |
| 30 | + neven = r / 2; |
44 | 31 | } else { |
45 | | - if (e > 0) { |
46 | | - count = multiplyCapped(e, rec(o, e - 1, 0)); |
47 | | - } |
| 32 | + neven = (r + 1) / 2; |
| 33 | + nodd = r / 2; |
48 | 34 | } |
49 | | - DP[o][e][req] = count; |
50 | | - return count; |
51 | | - } |
52 | | - |
53 | | - // Helper function to prevent overflow when multiplying |
54 | | - private long multiplyCapped(long a, long b) { |
55 | | - if (b == 0) { |
| 35 | + if (odd < nodd || even < neven) { |
56 | 36 | return 0; |
57 | 37 | } |
58 | | - if (a >= CAP || b >= CAP || a > CAP / b) { |
59 | | - return CAP; |
| 38 | + long oddways = helper(odd, nodd); |
| 39 | + long evenways = helper(even, neven); |
| 40 | + long total = oddways; |
| 41 | + if (evenways == 0 || total > INF / evenways) { |
| 42 | + total = INF; |
| 43 | + } else { |
| 44 | + total *= evenways; |
60 | 45 | } |
61 | | - return a * b; |
62 | | - } |
63 | | - |
64 | | - // Helper function to prevent overflow when adding |
65 | | - private long addCapped(long a, long b) { |
66 | | - long res = a + b; |
67 | | - return Math.min(res, CAP); |
| 46 | + return total; |
68 | 47 | } |
69 | 48 |
|
70 | 49 | public int[] permute(int n, long k) { |
71 | | - // Separate odd and even numbers from 1 to n |
72 | | - List<Integer> odds = new ArrayList<>(); |
73 | | - List<Integer> evens = new ArrayList<>(); |
74 | | - for (int x = 1; x <= n; x++) { |
75 | | - if ((x & 1) == 1) { |
76 | | - odds.add(x); |
| 50 | + List<Integer> ans = new ArrayList<>(); |
| 51 | + boolean first = false; |
| 52 | + boolean[] used = new boolean[n + 1]; |
| 53 | + int odd = (n + 1) / 2; |
| 54 | + int even = n / 2; |
| 55 | + int last = -1; |
| 56 | + for (int i = 1; i <= n; i++) { |
| 57 | + if (used[i]) { |
| 58 | + continue; |
| 59 | + } |
| 60 | + int odd2 = odd; |
| 61 | + int even2 = even; |
| 62 | + int cp = i & 1; |
| 63 | + int next = (cp == 1 ? 0 : 1); |
| 64 | + if (cp == 1) { |
| 65 | + odd2--; |
| 66 | + } else { |
| 67 | + even2--; |
| 68 | + } |
| 69 | + int r = n - 1; |
| 70 | + long cnt = solve(odd2, even2, r, next); |
| 71 | + if (k > cnt) { |
| 72 | + k -= cnt; |
77 | 73 | } else { |
78 | | - evens.add(x); |
| 74 | + ans.add(i); |
| 75 | + used[i] = true; |
| 76 | + odd = odd2; |
| 77 | + even = even2; |
| 78 | + last = cp; |
| 79 | + first = true; |
| 80 | + break; |
79 | 81 | } |
80 | 82 | } |
81 | | - // Count the number of odd and even elements |
82 | | - int oCount = odds.size(); |
83 | | - int eCount = evens.size(); |
84 | | - long ansTotal = rec(oCount, eCount, 2); |
85 | | - if (k > ansTotal) { |
| 83 | + if (!first) { |
86 | 84 | return new int[0]; |
87 | 85 | } |
88 | | - List<Integer> result = new ArrayList<>(); |
89 | | - int req = 2; |
90 | | - while (oCount + eCount > 0) { |
91 | | - List<Integer> candidates = new ArrayList<>(); |
92 | | - if (req == 2) { |
93 | | - int i = 0; |
94 | | - int j = 0; |
95 | | - while (i < odds.size() || j < evens.size()) { |
96 | | - if (j >= evens.size() || (i < odds.size() && odds.get(i) < evens.get(j))) { |
97 | | - candidates.add(odds.get(i++)); |
| 86 | + for (int z = 1; z < n; z++) { |
| 87 | + boolean taken = false; |
| 88 | + for (int j = 1; j <= n; j++) { |
| 89 | + if (!used[j] && ((j & 1) != last)) { |
| 90 | + int odd2 = odd; |
| 91 | + int even2 = even; |
| 92 | + int cp = j & 1; |
| 93 | + if (cp == 1) { |
| 94 | + odd2--; |
98 | 95 | } else { |
99 | | - candidates.add(evens.get(j++)); |
| 96 | + even2--; |
100 | 97 | } |
101 | | - } |
102 | | - } else if (req == 0) { |
103 | | - candidates.addAll(odds); |
104 | | - } else { |
105 | | - candidates.addAll(evens); |
106 | | - } |
107 | | - boolean found = false; |
108 | | - for (int num : candidates) { |
109 | | - int candidateParity = (num % 2 == 1) ? 0 : 1; |
110 | | - if (req != 2 && candidateParity != req) { |
111 | | - continue; |
112 | | - } |
113 | | - long ways; |
114 | | - if (candidateParity == 0) { |
115 | | - ways = rec(oCount - 1, eCount, 1); |
116 | | - } else { |
117 | | - ways = rec(oCount, eCount - 1, 0); |
118 | | - } |
119 | | - if (ways >= k) { |
120 | | - result.add(num); |
121 | | - if (candidateParity == 0) { |
122 | | - odds.remove(Integer.valueOf(num)); |
123 | | - oCount--; |
124 | | - req = 1; |
| 98 | + int r = n - (z + 1); |
| 99 | + int next = (cp == 1 ? 0 : 1); |
| 100 | + long cnt2 = solve(odd2, even2, r, next); |
| 101 | + if (k > cnt2) { |
| 102 | + k -= cnt2; |
125 | 103 | } else { |
126 | | - evens.remove(Integer.valueOf(num)); |
127 | | - eCount--; |
128 | | - req = 0; |
| 104 | + ans.add(j); |
| 105 | + used[j] = true; |
| 106 | + odd = odd2; |
| 107 | + even = even2; |
| 108 | + last = cp; |
| 109 | + taken = true; |
| 110 | + break; |
129 | 111 | } |
130 | | - found = true; |
131 | | - break; |
132 | | - } else { |
133 | | - k -= ways; |
134 | 112 | } |
135 | 113 | } |
136 | | - if (!found) { |
| 114 | + if (!taken) { |
137 | 115 | return new int[0]; |
138 | 116 | } |
139 | 117 | } |
140 | | - // Convert result list to array and return |
141 | | - int[] ans = new int[result.size()]; |
142 | | - for (int i = 0; i < result.size(); i++) { |
143 | | - ans[i] = result.get(i); |
144 | | - } |
145 | | - return ans; |
| 118 | + return ans.stream().mapToInt(i -> i).toArray(); |
146 | 119 | } |
147 | 120 | } |
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