Age Calculator: fix leap-year function and add time summary (days→hours/minutes/seconds)

Author: Ericbutler1209

Age Calculator/calculate.py

@@ -1,25 +1,25 @@
 import time
 from calendar import isleap
 
-def judge_leap_year(year):
-    if isleap(year):
-        return True
-    else:
-        return False
+# Check if a year is a leap year
+def judge_leap(year: int) -> bool:
+    return isleap(year)
 
-def month_days(month, leap_year):
+# Return number of days in a month, considering leap years
+def month_days(month: int, leap_year: bool) -> int:
     if month in [1, 3, 5, 7, 8, 10, 12]:
         return 31
     elif month in [4, 6, 9, 11]:
         return 30
     elif month == 2 and leap_year:
         return 29
-    elif month == 2 and (not leap_year):
+    else:
         return 28
 
-
+# User input
 name = input("Please enter your name: ")
-age = input("Please enter your age: ")
+age = int(input("Please enter your age: "))
+
 localtime = time.localtime(time.time())
 
 year = int(age)
@@ -29,16 +29,25 @@ def month_days(month, leap_year):
 begin_year = int(localtime.tm_year) - year
 end_year = begin_year + year
 
+# Count days in past years
 for y in range(begin_year, end_year):
-    if (judge_leap_year(y)):
-        day = day + 366
+    if judge_leap(y):
+        day += 366
     else:
-        day = day + 365
+        day += 365
 
-leap_year = judge_leap_year(localtime.tm_year)
+# Add days from current year
+leap_year = judge_leap(localtime.tm_year)
 for m in range(1, localtime.tm_mon):
-    day = day + month_days(m, leap_year)
-
-day = day + localtime.tm_mday
-print("\n\t%s's age is %d years or " % (name, year), end="")
-print("%d months or %d days" % (month, day))
+    day += month_days(m, leap_year)
+
+# Approximate breakdown (ignores time of day)
+hours = day * 24
+minutes = hours * 60
+seconds = minutes * 60
+
+print(f"\nHello {name}, you are approximately:")
+print(f"  {day:,} days")
+print(f"  {hours:,} hours")
+print(f"  {minutes:,} minutes")
+print(f"  {seconds:,} seconds old!")