A for loop construction

[SingL3]

If I have like multiple search engines depending on the config, and it is a list of search engine type:

search_engines = [
  search_engine_1,
  search_engine_2,
  ....
]

When I tried to construct a graph:

for i, se in enumerate(search_engines):
    graph.add_node(f"search_engine_{i}", se)

And after that, I only got results from one search engine(the last one).

[hinthornw]

Hi there! I'm not sure I fully understand the question so some elaboration could help.

Assuming each search_engine_* is a function - that for loop would add N nodes to your graph builder, but then the way you route to those nodes would still be determined by the edges you put in the graph.

[SingL3]

Oh, I am sorry. I didnt give the right example.

search_engines = [
  search_engine_1,
  search_engine_2,
  ....
]

for i, se in enumerate(search_engines):
    graph.add_node(f"search_engine_{i}", lambda state: {"search_results": se.invoke(query)})

[gbaian10]

In your example, using Send to aggregate the results might be more appropriate.

https://langchain-ai.github.io/langgraph/how-tos/map-reduce/