How to erased the frist node's output if we have two nodes in a single chained-graph #5627
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I’ve run into the same issue before — when chaining multiple nodes in a LangGraph, the intermediate node outputs end up visible even if we don’t want them shown. The fix is actually pretty straightforward: In your return {"risk_desc": risk_desc, "_internal_only": True} Then in your def counseling_node(state):
# your logic...
state.risk_desc = None # wipe the intermediate output
return {"final_plan": plan} Or even more cleanly: state.pop("risk_desc", None) That removes the key entirely. Quick tip: If you ever need more advanced control (like field-level privacy across the graph), I’ve built a semantic firewall layer on top of LangGraph for exactly this. Happy to share more if that becomes a thing. Good luck — hope your graph flows clean and your nodes stay quiet. |
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Glad it helped! Just in case you're building more complex LangGraph workflows — I recently compiled a structured map of common LLM issues (including graph traceability, memory drift, persona blending, etc.) and how to solve them at the reasoning layer. Might be useful if you plan to scale up or maintain reliability across sessions. Best of luck with your graph project — hope it flows clean and stays logically sharp! |
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I’ve run into the same issue before — when chaining multiple nodes in a LangGraph, the intermediate node outputs end up visible even if we don’t want them shown. The fix is actually pretty straightforward:
In your
classification_node
, mark the output as internal or just control what gets passed explicitly:Then in your
counseling_node
, just clear out that field manually if you don’t want it lingering:Or even more cleanly:
That removes the key entirely.
Quick tip:
Lan…