User#loginAnonymously use installation id to identify current device

Author: jwfing

core/src/main/java/cn/leancloud/LCUser.java

@@ -328,7 +328,7 @@ public static Observable<? extends LCUser> logIn(String username, String passwor
    * @return observable instance.
    */
   public static Observable<? extends LCUser> logInAnonymously() {
-    String anonymousId = UUID.randomUUID().toString().toLowerCase();
+    String anonymousId = LCInstallation.getCurrentInstallation().getInstallationId();
     Map<String, Object> param = new HashMap<>();
     param.put("id", anonymousId);
     return loginWithAuthData(param, AUTHDATA_PLATFORM_ANONYMOUS);

core/src/test/java/cn/leancloud/LCUserTest.java

@@ -39,6 +39,18 @@ protected void tearDown() throws Exception {
     ;
   }
 
+  public void testBunchAnonymousLogin() throws Exception {
+    LCUser user1 = LCUser.logInAnonymously().blockingFirst();
+    String anonymousUserId = user1.objectId;
+    user1.logOut();
+    for (int i = 0; i < 10; i++) {
+      user1 = LCUser.logInAnonymously().blockingFirst();
+      assertEquals(anonymousUserId, user1.objectId);
+      user1.logOut();
+      Thread.sleep(200);
+    }
+  }
+
   public void testSingupWithEmail() throws Exception {
     LCUser user = new LCUser();
     user.setEmail(EMAIL);