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[InstSimplify] Treat float binop with identity as refining (#120098)
If x is NaN, then fmul (x, 1) may produce a different NaN value.
Our float semantics explicitly permit folding fmul (x, 1) to x, but we
can't do this when we're replacing a select input, as selects are
supposed to preserve the exact bitwise value.
Fixes#115152 (comment).
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