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fix(runner): Fix complexity estimator method selection bug
- Set SOLUTION_METHOD env var before calling solve() so get_solver() picks the correct solution method instead of always using 'default' - Increase DEFAULT_SIZES to include 5000 for better O(n) vs O(n²) detection - Update Examples Gallery with dramatic O(n) vs O(n²) comparison (1818x diff) This fix enables accurate complexity estimation for multi-solution problems. Before: All methods showed similar times (bug) After: bruteforce correctly shows O(n²) with 5 second runtime at n=5000 Co-Authored-By: Claude Opus 4.5 <noreply@anthropic.com>
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docs/runner/README.md

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@@ -234,39 +234,57 @@ Peak 4.8MB | P95 4.8MB
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---
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### Example 5: Complexity Estimation
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### Example 5: Complexity Estimation (O(n) vs O(n²))
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This is the most impressive demonstration — showing the **dramatic difference** between O(n) and O(n²) algorithms.
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**Command:**
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```bash
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python runner/test_runner.py 0322_coin_change --estimate
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python runner/test_runner.py 0011_container --all --estimate
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```
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**Output:**
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**Output (O(n) Two Pointers):**
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```
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📈 Running complexity estimation...
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Mode: Direct call (Mock stdin, no subprocess overhead)
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Sizes: [10, 20, 50, 100, 200, 500, 1000, 2000]
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Runs per size: 3
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n= 100: 0.1286ms (avg of 3 runs)
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n= 500: 0.5394ms (avg of 3 runs)
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n= 1000: 1.0778ms (avg of 3 runs)
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n= 2000: 2.1274ms (avg of 3 runs)
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📌 Estimating: two_pointers
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n= 500: 0.34ms
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n= 1000: 0.51ms
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n= 2000: 1.24ms
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n= 5000: 2.78ms
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✅ Estimated: O(n)
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Confidence: 1.00
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Details: Linear: time = 0.038 + 0.001*n (sec)
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```
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**Output (O(n²) Brute Force):**
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```
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📌 Estimating: bruteforce
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n= 500: 43.59ms
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n= 1000: 195.59ms
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n= 2000: 782.44ms
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n= 5000: 5052.72ms ← 5 seconds!
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✅ Estimated: O(n²)
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Confidence: 1.00
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```
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**The Dramatic Difference:**
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| n | O(n) Two Pointers | O(n²) Brute Force | Ratio |
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|---|-------------------|-------------------|-------|
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| 1000 | 0.51ms | 196ms | 384x |
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| 2000 | 1.24ms | 782ms | 631x |
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| 5000 | 2.78ms | **5,053ms** | **1,818x** |
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**How to Interpret:**
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- Times should roughly double when n doubles for O(n) algorithms
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- `Confidence: 1.00` means the curve fit is excellent
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- `Details` shows the fitted formula: `time = constant + coefficient * f(n)`
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- For this DP problem, n represents the `amount` parameter
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- O(n): Time doubles when n doubles (linear growth)
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- O(n²): Time quadruples when n doubles (quadratic growth)
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- At n=5000, the O(n²) algorithm is **1,818x slower**
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- This is why algorithm complexity matters for large inputs!
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**Estimation Accuracy Tips:**
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**Estimation Tips:**
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- Works best when algorithm time dominates constant overhead
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- Very fast algorithms (< 0.1ms) may show inaccurate results
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- If estimated ≠ declared, try larger input sizes via generator
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- For fast algorithms, use larger n values (5000+) for accurate estimation
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- If estimated ≠ declared, the algorithm may have optimizations or the test sizes are too small
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---
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@@ -399,12 +417,12 @@ python runner/test_runner.py 0322_coin_change --estimate
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📈 Running complexity estimation...
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Mode: Direct call (Mock stdin, no subprocess overhead)
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Sizes: [10, 20, 50, 100, 200, 500, 1000, 2000]
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Sizes: [10, 20, 50, 100, 200, 500, 1000, 2000, 5000]
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Runs per size: 3
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n= 100: 0.1286ms (avg of 3 runs)
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n= 500: 0.5394ms (avg of 3 runs)
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n= 1000: 1.0778ms (avg of 3 runs)
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n= 2000: 2.1274ms (avg of 3 runs)
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n= 500: 0.54ms (avg of 3 runs)
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n= 1000: 1.08ms (avg of 3 runs)
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n= 2000: 2.13ms (avg of 3 runs)
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n= 5000: 5.31ms (avg of 3 runs)
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✅ Estimated: O(n)
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Confidence: 1.00
@@ -413,13 +431,14 @@ python runner/test_runner.py 0322_coin_change --estimate
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#### More Complexity Examples
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| Problem | Algorithm | Estimated | Confidence |
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|---------|-----------|-----------|------------|
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| 0322_coin_change | DP (1D) | O(n) | 1.00 |
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| 0084_largest_rectangle | Monotonic Stack | O(n log n) | 1.00 |
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| 0121_best_time | Single Pass | O(n log n) | 1.00 |
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| Problem | Algorithm | Declared | Estimated | Confidence |
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|---------|-----------|----------|-----------|------------|
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| 0011_container (two_pointers) | Two Pointers | O(n) | O(n) | 1.00 |
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| 0011_container (bruteforce) | Brute Force | O(n²) | **O(n²)** | 1.00 |
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| 0322_coin_change | DP (1D) | O(n×amount) | O(n) | 1.00 |
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| 0042_trapping (twopointer) | Two Pointers | O(n) | O(n) | 1.00 |
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> **Note:** The estimator uses curve fitting which may report O(n log n) for linear algorithms when constant overhead dominates at small input sizes. Verify with larger test inputs if needed.
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> **Note:** The estimator now uses sizes up to n=5000, which provides more accurate results for distinguishing O(n) from O(n²). For very fast algorithms where constant overhead dominates, the curve fitting may be less accurate.
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---
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runner/analysis/complexity.py

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@@ -58,7 +58,8 @@ class ComplexityEstimator:
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"""
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# Default sizes for estimation
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DEFAULT_SIZES = [10, 20, 50, 100, 200, 500, 1000, 2000]
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# Includes 5000 to better distinguish O(n) vs O(n²) algorithms
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DEFAULT_SIZES = [10, 20, 50, 100, 200, 500, 1000, 2000, 5000]
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# Number of times to run each size (for averaging)
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RUNS_PER_SIZE = 3
@@ -211,19 +212,25 @@ def get_memory_metrics(self) -> List[Tuple[int, int, float, int]]:
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def _run_with_mock_stdin(self, solve_func, input_data: str) -> Tuple[Optional[float], Optional[int]]:
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"""
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Run solve() with mocked stdin and capture execution time + memory.
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Args:
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solve_func: The solve() function to call
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input_data: Input string to feed via stdin
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Returns:
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Tuple of (elapsed_ms, peak_memory_bytes) or (None, None) on error
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"""
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import os
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original_stdin = sys.stdin
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original_stdout = sys.stdout
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original_method = os.environ.get('SOLUTION_METHOD')
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peak_bytes = None
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try:
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# Set the solution method for get_solver() to pick up
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if self.method:
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os.environ['SOLUTION_METHOD'] = self.method
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# Mock stdin with input data
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sys.stdin = io.StringIO(input_data)
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# Capture stdout to avoid output interference
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# Restore original stdin/stdout
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sys.stdin = original_stdin
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sys.stdout = original_stdout
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# Restore original SOLUTION_METHOD
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if original_method is not None:
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os.environ['SOLUTION_METHOD'] = original_method
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elif 'SOLUTION_METHOD' in os.environ:
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del os.environ['SOLUTION_METHOD']
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def _fit_complexity(self, sizes: List[int], times: List[float]) -> Optional[ComplexityResult]:
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"""Use big_O to fit complexity class."""

runner/complexity_estimator.py

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Original file line numberDiff line numberDiff line change
@@ -59,7 +59,8 @@ class ComplexityEstimator:
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"""
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# Default sizes for estimation
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DEFAULT_SIZES = [10, 20, 50, 100, 200, 500, 1000, 2000]
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# Includes 5000 to better distinguish O(n) vs O(n²) algorithms
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DEFAULT_SIZES = [10, 20, 50, 100, 200, 500, 1000, 2000, 5000]
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# Number of times to run each size (for averaging)
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RUNS_PER_SIZE = 3
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def _run_with_mock_stdin(self, solve_func, input_data: str) -> Tuple[Optional[float], Optional[int]]:
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"""
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Run solve() with mocked stdin and capture execution time + memory.
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Args:
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solve_func: The solve() function to call
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input_data: Input string to feed via stdin
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Returns:
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Tuple of (elapsed_ms, peak_memory_bytes) or (None, None) on error
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"""
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original_stdin = sys.stdin
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original_stdout = sys.stdout
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original_method = os.environ.get('SOLUTION_METHOD')
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peak_bytes = None
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try:
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# Set the solution method for get_solver() to pick up
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if self.method:
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os.environ['SOLUTION_METHOD'] = self.method
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# Mock stdin with input data
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sys.stdin = io.StringIO(input_data)
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# Capture stdout to avoid output interference
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# Restore original stdin/stdout
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sys.stdin = original_stdin
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sys.stdout = original_stdout
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# Restore original SOLUTION_METHOD
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if original_method is not None:
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os.environ['SOLUTION_METHOD'] = original_method
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elif 'SOLUTION_METHOD' in os.environ:
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del os.environ['SOLUTION_METHOD']
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def _fit_complexity(self, sizes: List[int], times: List[float]) -> Optional[ComplexityResult]:
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"""Use big_O to fit complexity class."""
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try:

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