NaN behaves strangely in a boolean expression #332
Description
I am using MathParser.org-mxparser 6.1.0, and with the below expressions I am getting strange results:
| formula | results |
|---|---|
| [NaN] == 1 | NaN |
| [NaN] == 1 && 0 == 0 | NaN |
| [NaN] == 1 && 1 == 0 | 0 |
| if([NaN] == 1 && 0 == 0, 1, 2) | NaN |
| if([NaN] == 1 && 1 == 0, 1, 2) | 2 |
I have checked a few programming languages handling of NaN and the equality operator returns false (for C# and Java).
So I was expecting [NaN] == 1 to return 0 above instead of NaN.
What is the logic behind this result?
Also why is the 3rd expression returning 0, compared to the 2nd which is returning NaN?