Call checkExpression eventhough there is no appropriate type from destructuring of array

Author: Kanchalai Tanglertsampan

src/compiler/checker.ts

@@ -4447,9 +4447,14 @@ namespace ts {
             return property;
         }
 
-        // Return the symbol for the property with the given name in the given type. Creates synthetic union properties when
-        // necessary, maps primitive types and type parameters are to their apparent types, and augments with properties from
-        // Object and Function as appropriate.
+        /**
+         * Return the symbol for the property with the given name in the given type. Creates synthetic union properties when
+         * necessary, maps primitive types and type parameters are to their apparent types, and augments with properties from
+         * Object and Function as appropriate.
+         *
+         * @param type a type to look up property from
+         * @param name a name of property to look up in a given type
+         */
         function getPropertyOfType(type: Type, name: string): Symbol {
             type = getApparentType(type);
             if (type.flags & TypeFlags.ObjectType) {
@@ -12856,6 +12861,9 @@ namespace ts {
                         return checkDestructuringAssignment(element, type, contextualMapper);
                     }
                     else {
+                        // We still need to check element expression here because we may need to set appropriate flag on the expression
+                        // such as NodeCheckFlags.LexicalThis on "this"expression.
+                        checkExpression(element);
                         if (isTupleType(sourceType)) {
                             error(element, Diagnostics.Tuple_type_0_with_length_1_cannot_be_assigned_to_tuple_with_length_2, typeToString(sourceType), (<TupleType>sourceType).elementTypes.length, elements.length);
                         }