fix check for default export

Author: Gabriela Araujo Britto

src/services/findAllReferences.ts

@@ -1196,7 +1196,9 @@ namespace ts.FindAllReferences.Core {
 
         // For `export { foo as bar }`, rename `foo`, but not `bar`.
         if (!isForRenameWithPrefixAndSuffixText(state.options) || alwaysGetReferences) {
-            const exportKind = referenceLocation.originalKeywordKind === SyntaxKind.DefaultKeyword ? ExportKind.Default : ExportKind.Named;
+            const isDefaultExport = referenceLocation.originalKeywordKind === SyntaxKind.DefaultKeyword
+                || exportSpecifier.name.originalKeywordKind === SyntaxKind.DefaultKeyword;
+            const exportKind = isDefaultExport ? ExportKind.Default : ExportKind.Named;
             const exportSymbol = Debug.assertDefined(exportSpecifier.symbol);
             const exportInfo = Debug.assertDefined(getExportInfo(exportSymbol, exportKind, state.checker));
             searchForImportsOfExport(referenceLocation, exportSymbol, exportInfo, state);

src/services/importTracker.ts

@@ -269,7 +269,7 @@ namespace ts.FindAllReferences {
         }
 
         /**
-         * `import x = require("./x") or `import * as x from "./x"`.
+         * `import x = require("./x")` or `import * as x from "./x"`.
          * An `export =` may be imported by this syntax, so it may be a direct import.
          * If it's not a direct import, it will be in `indirectUsers`, so we don't have to do anything here.
          */