Use a subpath without nginx or something similar

[JVT038]

Hi,
So I want to run a SocketIO application without the use of NGINX or something similar to it.
I'm just running the instance like this: socketio.run(app, str(host), int(port), log_output=strtobool(str(log_output))), and I would like to run the instance on 127.0.0.1:5000/subpath instead of only the address:port.
Is it possible to do this, without NGINX?

[miguelgrinberg]

Socket.IO always runs on a subpath. The default location of the Socket.IO endpoint is on the /socket.io path. You never see this because neither the client nor the server require you to enter this path, it is just appended to the server URL that your application uses.

If you want to change this path, you can, but it is not done by changing the connection URL. In the JavaScript and Python implementations of Socket.IO, the path of the Socket.IO endpoint is given in a path option, separate from the server specification.

[JVT038]

I believe you misunderstood me.
What I meant was that I could actually access the website / Flask application on a subpath.
And since the server / Flask application is started with the socketio.run() function, I decided to ask here.
So I want to visit my Flask app on 127.0.0.1:5000/subpath.

[miguelgrinberg]

There are a few ways to do this, but one that I find very easy is to put all the application routes inside a blueprint, then you can register the blueprint with a url_prefix.

[JVT038]

Thanks, it worked!