Is there a way to define custom operator? #1497
Unanswered
flavono123
asked this question in
Q&A
Replies: 1 comment
-
Not yet! Feel free to raise an enhancement request - though truth be told I have no idea how to implement it 😓 |
Beta Was this translation helpful? Give feedback.
0 replies
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
Uh oh!
There was an error while loading. Please reload this page.
-
Like jq's defining functions(orgin doc).
Beta Was this translation helpful? Give feedback.
All reactions