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Tube_Code_fast.m
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175 lines (130 loc) · 4.25 KB
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% this is a code for modelling of concentric tube robot in free space based on " Design
% and Control of Concentric-Tube Robots " by Dupont
clearvars
clc
%% Initializing parameters
param % load tube parameters inside param.m file
tic
l=0.01*[55 30 20]; % length of tubes
B=0.01*[-35 -15 -10]; % length of tubes before template
l_k=0.01*[10 10 15]; % length of curved part of tubes
%initial angles
alpha_1=3*pi/2;
alpha_2=pi/2;
alpha_3=pi;
alpha=[alpha_1 alpha_2 alpha_3];
% segmenting tubes
% check all inputs must have n elements, n is number of tubes
[L,d_tip,EE,UUx,UUy,II,GG,JJ] = segmenting(E,Ux,Uy,I,G,J,l,B,l_k);
k=length(l);
figure(2)
xlabel('S [mm]')
hold on
for i=1:k
plot(linspace(B(i),d_tip(i),10),i*ones(1,10),'r' ,'LineWidth',i*1.5)
end
SS=L;
for i=1:length(L)
SS(i)=sum(L(1:i));
plot((B(1)+SS(i))*ones(1,10),1:10,'b' ,'LineWidth',2)
end
hold off
% S is segmented abssica of tube after template
S=SS(SS+min(B)>0)+min(B);
E=zeros(n,length(S)); I=E; G=E; J=E; Ux=E; Uy=E;
for i=1:n
E(i,:)=EE(i,SS+min(B)>0); I(i,:)=II(i,SS+min(B)>0); G(i,:)=GG(i,SS+min(B)>0);
J(i,:)=JJ(i,SS+min(B)>0); Ux(i,:)=UUx(i,SS+min(B)>0); Uy(i,:)=UUy(i,SS+min(B)>0);
end
% each (i,j) element of above matrices correspond to the jth segment of
% ith tube, 1st tube is the most inner
%% Solving ode for segments
span=[0 S]; % vector of tube abssica starting at zero
Length=[]; r=[]; U_z=[]; % solved length, curvatures, and twist angles
%U1_after=[0;0;0]; % 1st tube initial curvature at segment beginning
r0=[ 0 0 0]'; R0=[cos(alpha_1) -sin(alpha_1) 0; sin(alpha_1) cos(alpha_1) 0; 0 0 1];
uz_0=[0 0 0]';
R0=reshape(R0',[9,1]);
for seg=1:length(S)
s_span = [span(seg) span(seg+1)-0.0000001];
y0_1=[r0 ; R0];
y0_2=zeros(2*n,1);
y0_2(n+1:2*n)=alpha;
y0_2(1:n)=uz_0;
y_0=[y0_2; y0_1];
[s,y] = ode45(@(s,y) ode5(s,y,Ux(:,seg),Uy(:,seg),E(:,seg),I(:,seg),G(:,seg),J(:,seg),n), s_span, y_0);
% first n elements of y are curvatures along z, e.g., y= [ u1_z u2_z ... ]
% last n elements of y are twist angles, alpha_i
shape=[y(:,2*n+1),y(:,2*n+2),y(:,2*n+3)];
Length=[Length; s];
r=[r; shape];
U_z=[U_z; y(:,1:n )];
r0=shape(end,:)';
R0=y(end,2*n+4:2*n+12)';
uz_0=[U_z(end,:)]';
alpha=[y(end,n+1),y(end,n+2),y(end,n+3)]';
end
Uz=zeros(n,1);
for i=1:n
[a,index] = min( abs(Length-d_tip(i)+0.0001) );
Uz(i)= U_z(index,i);
end
[~, tube2_end] = min(abs(Length-d_tip(2)));
r2=[r(1:tube2_end,1),r(1:tube2_end,2),r(1:tube2_end,3)];
[~, tube3_end] = min(abs(Length-d_tip(3)));
r3=[r(1:tube3_end,1),r(1:tube3_end,2),r(1:tube3_end,3)];
figure(1);
plot3(r(:,1),r(:,2),r(:,3),'b','LineWidth',2)
hold on
plot3(r2(:,1),r2(:,2),r2(:,3),'r','LineWidth',4)
plot3(r3(:,1),r3(:,2),r3(:,3),'g','LineWidth',6)
xlabel('X [mm]'); ylabel('Y [m]'); zlabel('Z [m]')
grid on
axis equal
toc
%% ODE
function dydt = ode5(~,y,Ux,Uy,E,I,G,J,n)
dydt=zeros(2*n+12,1);
% first n elements of y are curvatures along z, e.g., y= [ u1_z u2_z ... ]
% second n elements of y are twist angles, alpha_i
% last 12 elements are r (position) and R (orientations), respectively
% calculating summation of matrices
K=zeros(3,3);SUM=zeros(3,1);
for i=1:n
k=diag([E(i)*I(i) E(i)*I(i) G(i)*J(i)] );
sum=[cos(y(n+i)) -sin(y(n+i)) 0; sin(y(n+i)) cos(y(n+i)) 0; 0 0 1]*k*[Ux(i); Uy(i); 0];
K=K+k;
SUM=SUM+sum;
end
% calculating 1st tube's curvatures in x and y direction
ux=zeros(n,1);uy=zeros(n,1);
% calculating tube's curvatures in x and y direction
for i=1:n
u= K\([cos(y(n+i)) sin(y(n+i)) 0; -sin(y(n+i)) cos(y(n+i)) 0; 0 0 1] * SUM );
ux(i)=u(1); uy(i)=u(2);
end
% odes for twist
for i=1:n
if G(i)==0
G(i)=1; J(i)=1; % to avoid singularity when tube doesn't exist
end
dydt(i)= ( (E(i)*I(i))/(G(i)*J(i)) ) * ( ux(i)* Uy(i) - uy(i)* Ux(i) ); % ui_z
dydt(n+i)= y(i); %alpha_i
end
e3=[0 0 1]';
uz = y(1:n);
% y(1) to y(3) are position of point materials
%r1=[y(1); y(2); y(3)];
% y(4) to y(12) are rotation matrix elements
R1=[y(2*n+4) y(2*n+5) y(2*n+6);y(2*n+7) y(2*n+8) y(2*n+9);y(2*n+10) y(2*n+11) y(2*n+12)];
u_hat=[0 -uz(1) uy(1) ; uz(1) 0 -ux(1) ; -uy(1) ux(1) 0 ];
% odes
dr1 = R1*e3;
dR1=R1*u_hat;
dydt(2*n+1)=dr1(1);dydt(2*n+2)=dr1(2);dydt(2*n+3)=dr1(3);
dR=dR1';
dR=dR(:);
for i=4:12
dydt(2*n+i)=dR(i-3);
end
end