binary number

import java.io.*;
import java.util.*;

public class Solution {
    

    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        
        Scanner scan = new Scanner(System.in);
        int number = scan.nextInt();
        int tempCount = 0;
        int maxCount = 0;
     
        String s = new String();
        s = "";
        
        while(number > 0){
            
            s = s + (number % 2);
            number = number >> 1;
        }
        
        String[] obj = s.split("0");
        Arrays.sort(obj);
        System.out.print(obj[obj.length - 1].length());
        
       /* while(!stack.isEmpty()) {
            if(stack.pop() == 1){
                tempCount++;
                maxCount = tempCount;
                while(stack.pop() == 1) {
                    tempCount++;
                    maxCount = tempCount;
                }
                tempCount = 0;
            }
            else
                continue;
        }
        
        int answer = (tempCount > maxCount) ? tempCount : maxCount;
        
       // Integer n = 439;
        //System.out.println(Integer.toBinaryString(n))
        */
        //System.out.print(answer);
        
    }
}