Skip to content
Discussion options

You must be logged in to vote

I think the problem is that you have to define a "default" container via process.container, even if all of your processes are covered via withName / withLabel. Also, not sure if withName / withLabel are case-sensitive ...

Replies: 1 comment 1 reply

Comment options

You must be logged in to vote
1 reply
@avw-adifranco
Comment options

Answer selected by avw-adifranco
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment