Grover behaves differently for qc and for a qint register

[ItaiTzur76]

.Grover() behaves differently when invoked on qc and on a register created by a qint.new call.

Reproduce:

1. Open http://oreilly-qc.github.io?p=6-2 and click on the Run Program button. Observe the Program circuit and Circle notation sections.
2. Replace the reg.Grover() call with qc.Grover() in line 26.
3. Click on the Run Program button again.

Expected behavior:
The output in the Program circuit and Circle notation sections is the same as before, since reg was initialized in line 13 to contain all qubits.

Actual behavior:
The output in the Program circuit and Circle notation sections is different.