CYW43 accesspoint uncertain what to pass for param security to enable WPA2 mixed PSK

[RichardB-RT]

In micropython i am enabling an accesspoint using the following code:

network.WLAN.config(essid=ssid, password=password, channel=1, security=4)

However, connecting to this AP does not work. When i change the code to:

network.WLAN.config(essid=ssid, password=password)

it does work. A connection can be made to this accesspoint.
Requesting the security parameter after successful connection with:

print(network.WLAN.config('security')) 

reveals that the security param is set to 0x00400006 which is CYW43_AUTH_WPA2_MIXED_PSK as defined in the cyw43 code.

What i am unable to find is the correct value for security to pass in micropython to select the CYW43_AUTH_WPA2_MIXED_PSKin the cyw43 driver.
This value is passed to cyw43_wifi_ap_set_auth() in network_cyw43.c.

network.WLAN.config(essid=ssid, password=password, channel=1, security=??????)

[RichardB-RT]

I figured it out myself. It seams to be that the 0x00400006 value is to be passed to the security parameter, so

network.WLAN.config(essid=ssid, password=password, channel=1, security=0x00400006)

has the same result as

network.WLAN.config(essid=ssid, password=password)