don't want to write each field test . I want overall test .please help me

[NarenderSiri]

const schema = yup.object().shape({
tax: yup.string().required("Tax is Required").test("","Remove white spaces" ,(value)=>!!value.trim()),
taxName: yup.string().required("Tax Name is Required").test("","Remove white spaces" ,(value)=>!!value.trim()),
countryName: yup.string().required("Country Name is Required").test("","Remove white spaces" ,(value)=>!!value.trim()),
});

[bluebill1049]

Don't think there is alternative, schema will need to declare each input validation rules.

[Moshyfawn]

You can simply create a validation schema base / factory and extend it with field specific operators like:

const createBaseFieldSchema = (name: string) =>
  yup.string().required(`${name} is Required`).test("", "Remove white spaces", (value) => !!value.trim())

const schema = yup.object({
  tax: createBaseFieldSchema("tax").min(2, "2 MIN")
})

[NarenderSiri]

But name is getting undefined .
Example: undefined is required .

but I want tax is required

[Moshyfawn]

You should pass your field name to the createBaseFieldSchema to have a proper error message. See this codesandbox

[NarenderSiri]

It is not working.please check
codesandbox

[Moshyfawn]

Your factory function expects a named argument name, but you're passing a string instead.

• Either update your function from ({ name }) to (name)
• or pass your field name to the factory function as a named argument createBaseFieldSchema({ name: "tax })

[NarenderSiri]

Tq so much

[Moshyfawn]

No problem!