DOC: fix SA01, ES01 for pandas.arrays.IntervalArray.mid

Author: tuhinsharma121

ci/code_checks.sh

@@ -133,7 +133,6 @@ if [[ -z "$CHECK" || "$CHECK" == "docstrings" ]]; then
         -i "pandas.arrays.IntegerArray SA01" \
         -i "pandas.arrays.IntervalArray.left SA01" \
         -i "pandas.arrays.IntervalArray.length SA01" \
-        -i "pandas.arrays.IntervalArray.mid SA01" \
         -i "pandas.arrays.IntervalArray.right SA01" \
         -i "pandas.arrays.NumpyExtensionArray SA01" \
         -i "pandas.arrays.SparseArray PR07,SA01" \

pandas/core/arrays/interval.py

@@ -1291,6 +1291,16 @@ def mid(self) -> Index:
         """
         Return the midpoint of each Interval in the IntervalArray as an Index.
 
+        The midpoint of an interval is calculated as the average of its
+        `left` and `right` bounds. This property returns a `pandas.Index` object
+        containing the midpoint for each interval.
+
+        See Also
+        --------
+        Interval.left : Return left bound for the interval.
+        Interval.right : Return right bound for the interval.
+        Interval.length : Return the length of each interval.
+
         Examples
         --------