Get proper name with inspect, remove need for giving __name__.

Author: T4rk1n

dash/_utils.py

@@ -10,6 +10,7 @@
 import json
 import secrets
 import string
+import inspect
 from html import escape
 from functools import wraps
 from typing import Union
@@ -281,3 +282,12 @@ def hooks_to_js_object(hooks: Union[RendererHooks, None]) -> str:
 
 def parse_version(version):
     return tuple(int(s) for s in version.split("."))
+
+
+def get_caller_name(name: str):
+    stack = inspect.stack()
+    for s in stack:
+        for code in s.code_context:
+            if f"{name}(" in code:
+                return s.frame.f_locals.get("__name__", "__main__")
+    return "__main__"

dash/dash.py

@@ -55,6 +55,7 @@
     gen_salt,
     hooks_to_js_object,
     parse_version,
+    get_caller_name,
 )
 from . import _callback
 from . import _get_paths
@@ -387,14 +388,16 @@ def __init__(  # pylint: disable=too-many-statements
     ):
         _validate.check_obsolete(obsolete)
 
+        caller_name = get_caller_name(self.__class__.__name__)
+
         # We have 3 cases: server is either True (we create the server), False
         # (defer server creation) or a Flask app instance (we use their server)
         if isinstance(server, flask.Flask):
             self.server = server
             if name is None:
-                name = getattr(server, "name", "__main__")
+                name = getattr(server, "name", caller_name)
         elif isinstance(server, bool):
-            name = name if name else "__main__"
+            name = name if name else caller_name
             self.server = flask.Flask(name) if server else None
         else:
             raise ValueError("server must be a Flask app or a boolean")