Skip to content

Commit c7b8a78

Browse files
committed
Fix latex in perp flap readme
1 parent 76896cb commit c7b8a78

File tree

1 file changed

+1
-1
lines changed

1 file changed

+1
-1
lines changed

perpendicular-flap/README.md

Lines changed: 1 addition & 1 deletion
Original file line numberDiff line numberDiff line change
@@ -11,7 +11,7 @@ We model a two-dimensional fluid flowing through a channel. A solid, elastic fla
1111

1212
![Flap setup](images/tutorials-perpendicular-flap-setup-drawing.png)
1313

14-
The simulated flow domain is 6 units long (x) and 4 units tall (y). The flap is located at the center of the bottom (x=0) and is 1 unit long (y) and 0.1 units thick (x). We set the fluid density $$ \{rho}_F= 1.0kg/m^{3} $$, the kinematic viscosity $$ \{nu}_f= 1.0m^{2}/s $$, the solid density $$ \{rho}_s= 3.0·10^{3}kg/m^{3} $$, the Young’s modulus to $$ E= 4.0·10^{6} kg/ms^{2} $$ and the Poisson ratio $$ \{nu}_s = 0.3 $$. On the left boundary a constant inflow profile in x-direction of 10m/s is prescribed. The right boundary is an outflow and the top and bottom of the channel as well as the surface of the flap are no-slip walls.
14+
The simulated flow domain is 6 units long (x) and 4 units tall (y). The flap is located at the center of the bottom (x=0) and is 1 unit long (y) and 0.1 units thick (x). We set the fluid density $$ \rho_F= 1.0kg/m^{3} $$, the kinematic viscosity $$ \nu_f= 1.0m^{2}/s $$, the solid density $$ \rho_s= 3.0·10^{3}kg/m^{3} $$, the Young’s modulus to $$ E= 4.0·10^{6} kg/ms^{2} $$ and the Poisson ratio $$ \nu_s = 0.3 $$. On the left boundary a constant inflow profile in x-direction of 10m/s is prescribed. The right boundary is an outflow and the top and bottom of the channel as well as the surface of the flap are no-slip walls.
1515

1616
## Available solvers
1717

0 commit comments

Comments
 (0)