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As outlined in #4323, this can be achieved by a list of events:

(src=0, dst=1, time=t1)
(src=0, dst=2, time=t2)
(src=1, dst=2, time=t2)

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@DogitoErgoSum
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@rusty1s
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@DogitoErgoSum
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@rusty1s
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Answer selected by DogitoErgoSum
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