calculations

Author: aditya520

pages/home/pyth-token/oracle-integrity-staking/examples.mdx

@@ -107,10 +107,13 @@ $$
 \quad{R^p_p} &= {r} \times min({S^p_p}, {C}_p) = 10\% \times 200 = 20 \\
 \quad{R^d_p} &= {R_p} - {R^p_p} = 50 - 20 = 30 \\
 \text{Fee paid by Delegator} \quad{F^d_p} &= {f} \times {R^d_p} = 2\% \times 30 = 0.6 \\
+\text{Final Delegator Reward} \quad{R^d_p} &= {R^d_p} - {F^d_p} = 30 - 0.6 = 29.4 \\
+\text{Total Publisher Reward} \quad{R^p_p} &= {R^p_p} + {F^d_p} = 20 + 0.6 = 20.6 \\
 
 \text{Slashed percentage}\quad{z} &= 50\% \\
-\text{Final Delegator Reward} \quad{\Pi^d_p} &= ( R^p_p + f \cdot R^d_p ) - z \cdot S^p_p = (20 + 0.6) - 0.5 \cdot 200 = 20.6 - 100 = -79.4 \\
-\text{Total Publisher Reward} \quad{\Pi^p_p} &= {R^p_p} + {F^d_p} = 20 + 0.6 = 20.6 \\
+
+\text{Net Publisher Stake} \quad{\Pi^p_p} = ( R^p_p + f \cdot R^d_p ) - z \cdot S^p_p = (20 + 0.6) - 0.5 \cdot 200 = 20.6 - 100 = -79.4 \\
+\text{Net Deligator Stake} \quad{\Pi^d_p} = R^d_p - ( f \cdot R^d_p + z \cdot S^d_p ) = 30 - ( 0.6 + 0.5 \cdot 300 ) = 30 - 150.6 = -120.6 \\
 \end{aligned}
 $$