fixing symbology

Author: YaserJazouane

pages/home/oracle-integrity-staking/examples.mdx

@@ -122,7 +122,7 @@ In this scenario, let's assume that
 
 - The constant parameter representing the target stake per symbol $M$ is 100
 - The constant parameter to control cap contribution $Z$ is 5
-- Current symbols published are {$s_{1}$,.., $s_{5}$} where for every symbol currently published $n_s$ = 5 (for i = 1 .. 5 $n_{s_i}$ = 5)
+- Current symbols published are \{$s_{1}$,.., $s_{5}$\} where for every symbol currently published $n_s$ = 5 (for i = 1 .. 5 $n_{s_i}$ = 5)
 
 The cap of the pool is calculated as follows:
 
@@ -153,9 +153,9 @@ $$
 
 ### Option 2: Publish additional symbols where cap of 32 publishers is not reached
 
-Assuming there is room to publish 5 more symbols {$s_{6}$,.., $s_{10}$} where each have currently 9 publishers ( for i = 6 .. 10 $n_{s_i}$ = 9)
+Assuming there is room to publish 5 more symbols \{$s_{6}$,.., $s_{10}$\} where each have currently 9 publishers ( for i = 6 .. 10 $n_{s_i}$ = 9)
 
-The new pool cap would change as the sum of the current cap from the 5 symbols published plus the cap gained from publishing the additional symbols {$s_{6}$,.., $s_{10}$} (where for i = 6 .. 10 $n_{s_i}$ = 10)
+The new pool cap would change as the sum of the current cap from the 5 symbols published plus the cap gained from publishing the additional symbols \{$s_{6}$,.., $s_{10}$\} (where for i = 6 .. 10 $n_{s_i}$ = 10)
 
 $$
 \begin{aligned}