Skip to content

Commit fa0f0fd

Browse files
committed
minor fixes to symbology
1 parent 6659f41 commit fa0f0fd

File tree

1 file changed

+3
-3
lines changed

1 file changed

+3
-3
lines changed

pages/home/oracle-integrity-staking/examples.mdx

Lines changed: 3 additions & 3 deletions
Original file line numberDiff line numberDiff line change
@@ -122,7 +122,7 @@ In this scenario, let's assume that
122122

123123
- The constant parameter representing the target stake per symbol $M$ is 100
124124
- The constant parameter to control cap contribution $Z$ is 5
125-
- Current symbols published are $\{$s_{1}$,.., $s_{5}$\}$ where for every symbol currently published $n_s$ = 5 (for i = 1 .. 5 $n_{s_i}$ = 5)
125+
- Current symbols published are {$s_{1}$,.., $s_{5}$} where for every symbol currently published $n_s$ = 5 (for i = 1 .. 5 $n_{s_i}$ = 5)
126126

127127
The cap of the pool is calculated as follows:
128128

@@ -153,9 +153,9 @@ $$
153153

154154
### Option 2: Publish additional symbols where cap of 32 publishers is not reached
155155

156-
Assuming there is room to publish 5 more symbols $\{$s_{6}$,.., $s_{10}$\}$ where each have currently 9 publishers ( for i = 6 .. 10 $n_{s_i}$ = 9)
156+
Assuming there is room to publish 5 more symbols {$s_{6}$,.., $s_{10}$} where each have currently 9 publishers ( for i = 6 .. 10 $n_{s_i}$ = 9)
157157

158-
The new pool cap would change as the sum of the current cap from the 5 symbols published plus the cap gained from publishing the additional symbols $\{$s_{6}$,.., $s_{10}$\}$ (where for i = 6 .. 10 $n_{s_i}$ = 10)
158+
The new pool cap would change as the sum of the current cap from the 5 symbols published plus the cap gained from publishing the additional symbols {$s_{6}$,.., $s_{10}$} (where for i = 6 .. 10 $n_{s_i}$ = 10)
159159

160160
$$
161161
\begin{aligned}

0 commit comments

Comments
 (0)