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docsDocumentation in the Doc dirDocumentation in the Doc dirtype-featureA feature request or enhancementA feature request or enhancement
Description
Proposal:
from itertools import repeat
from operator import getitemtuple, itemtuplegetter
obj = ['a', 'b']
indices = [0, 1, 2, 3]
defaults = repeat(None)
itg = itemtuplegetter(indices, defaults=defaults)
print(itg(obj))
# ('a', 'b', None, None)
print(getitemtuple(obj, indices, defaults))
# ('a', 'b', None, None)
Other form was considered: itemitergetter()() -> Iterator
.
But its performance has turned out to be non-competitive (see discourse discusssion).
Thus, it is best to follow tuple
return same as existing itemtgetter
.
Has this already been discussed elsewhere?
No response given
Links to previous discussion of this feature:
https://discuss.python.org/t/itemgetter-split-into-2-objects/69020/33
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docsDocumentation in the Doc dirDocumentation in the Doc dirtype-featureA feature request or enhancementA feature request or enhancement
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