Incorrect Output When Printing Bytes Type

[1m-noob]

Bug report

Bug description:

from pathlib import Path
Info = Path("build/Info.bin").read_bytes()#.hex()
print(Info)
print(Info.hex())

here's the output:

b'\x01\x00\xc22\x00\x00\x00\x00\x00\x00'
0100c232000000000000

CPython versions tested on:

3.13, 3.10

Operating systems tested on:

Windows

[zware]

You're going to have to clarify what you believe to be wrong here; the output looks correct to me.

Edit: I think I see it now; the \xc22\x00 part, which you expect to be \xc2\x32\x00? It is correct as is; hex(ord('2')) == '0x32'. Byte values in the range of the ASCII character set are rendered as those characters rather than as their hex form. This is useful for binary protocols that include ASCII, but can be confusing in cases like this where ASCII characters are embedded in an otherwise "random" collection of bytes. It's generally not that useful to print such bytes, though; if you need to view them, you may want to use a different method (such as the .hex() method that you already found).

[StanFromIreland]

You're going to have to clarify what you believe to be wrong here; the output looks correct to me.

+1 This should be closed as not planned.

I presume the misunderstanding was the difference, which is in fact, correct.

Python 3.14.0a7+ (heads/main:f3d877a27ab, Apr 18 2025, 11:20:56) [GCC 14.2.1 20250110 (Red Hat 14.2.1-7)] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> b'\x01\x00\xc22\x00\x00\x00\x00\x00\x00'.hex()
'0100c232000000000000'

[1m-noob]

Edit: I think I see it now; the \xc22\x00 part, which you expect to be \xc2\x32\x00? It is correct as is; hex(ord('2')) == '0x32'. Byte values in the range of the ASCII character set are rendered as those characters rather than as their hex form. This is useful for binary protocols that include ASCII, but can be confusing in cases like this where ASCII characters are embedded in an otherwise "random" collection of bytes. It's generally not that useful to print such bytes, though; if you need to view them, you may want to use a different method (such as the .hex() method that you already found).

thank u, it's helpful