How to obtain REST URI Template

[jimbogithub]

I need to obtain the REST URI Template, e.g. given: @Path("test/{p1}/{p2}/extra/{p2}") I literally want the "test/{p1}/{p2}/extra/{p2}" including any parent relative path component. I do not want the path with parameters replaced such as UriInfo::getPath() provides.

Is there a way to do it?

It can't be reverse engineered reliably from UriInfo::getPathSegments and UriInfo ::getPathParameters as a fixed path segment may have the same name as a param value.

It's tricky to derive it from the endpoint annotations as you would have to check class and method and root etc.

It looks like it might be available at VertxResteasyReactiveRequestContext::getTarget().getClassPath().template but there's no way to obtain that.

FWIW Spring makes this available at HttpServletRequest::getAttribute(org.springframework.web.servlet.HandlerMapping.BEST_MATCHING_PATTERN_ATTRIBUTE)

[jimbogithub]

OK, it can be done, but is pretty dirty:

@Context
ServerRequestContext ctx;

@GET
@Path("test/{p1}/{p2}/more/{p3}")
public String test() {
	ClientProxy proxy = (ClientProxy) ctx;
	ResteasyReactiveRequestContext rtx = (ResteasyReactiveRequestContext) proxy.arc_contextualInstance();
	String template = rtx.getTarget().getPath().template;
	LOG.info("{}", template);
	return template;
}

Can we enhance Quarkus to expose this in a supported way?