tests - correctly handle finding output in project of type default

Author: cderv

tests/utils.ts

@@ -62,10 +62,8 @@ export function findProjectOutputDir(projectdir: string | undefined) {
   if (type === "manuscript") {
     return (yaml as any)?.project?.["output-dir"] || "_manuscript";
   }
-  if (type === "default") {
-    return (yaml as any)?.project?.["output-dir"];
-  }
-  return (yaml as any)?.project?.["output-dir"];
+  // type default explicit or just unset
+  return (yaml as any)?.project?.["output-dir"] || "";
 }
 
 // Gets output that should be created for this input file and target format
@@ -142,10 +140,10 @@ export function outputForInput(
     }
   }
 
-  const outputPath: string = projectRoot && projectOutDir
+  const outputPath: string = projectRoot && projectOutDir !== undefined
       ? join(projectRoot, projectOutDir, dir, `${stem}.${outputExt}`)
       : join(dir, `${stem}.${outputExt}`);
-  const supportPath: string = projectRoot && projectOutDir
+  const supportPath: string = projectRoot && projectOutDir !== undefined
     ? join(projectRoot, projectOutDir, dir, `${stem}_files`)
     : join(dir, `${stem}_files`);