feat: add js solution to lc problem: No.0273

Author: rain84

solution/0200-0299/0273.Integer to English Words/README.md

@@ -322,6 +322,32 @@ function numberToWords(num: number): string {
 }
 ```
 
+#### JavaScript
+
+```js
+function numberToWords(num) {
+    if (num === 0) return 'Zero';
+
+    // prettier-ignore
+    const f = (x) => {
+    const dict1 = ['','One','Two','Three','Four','Five','Six','Seven','Eight','Nine','Ten','Eleven','Twelve','Thirteen','Fourteen','Fifteen','Sixteen','Seventeen','Eighteen','Nineteen',]
+    const dict2 = ['','','Twenty','Thirty','Forty','Fifty','Sixty','Seventy','Eighty','Ninety',]
+    let ans = ''
+
+    if (x <= 19) ans = dict1[x] ?? ''
+    else if (x < 100) ans = `${dict2[Math.floor(x / 10)]} ${f(x % 10)}`
+    else if (x < 10 ** 3) ans = `${dict1[Math.floor(x / 100)]} Hundred ${f(x % 100)}`
+    else if (x < 10 ** 6) ans = `${f(Math.floor(x / 10 ** 3))} Thousand ${f(x % 10 ** 3)}`
+    else if (x < 10 ** 9) ans = `${f(Math.floor(x / 10 ** 6))} Million ${f(x % 10 ** 6)}`
+    else ans = `${f(Math.floor(x / 10 ** 9))} Billion ${f(x % 10 ** 9)}`
+
+    return ans.trim()
+  }
+
+    return f(num);
+}
+```
+
 <!-- tabs:end -->
 
 <!-- solution:end -->

solution/0200-0299/0273.Integer to English Words/README_EN.md

@@ -320,6 +320,32 @@ function numberToWords(num: number): string {
 }
 ```
 
+#### JavaScript
+
+```js
+function numberToWords(num) {
+    if (num === 0) return 'Zero';
+
+    // prettier-ignore
+    const f = (x) => {
+    const dict1 = ['','One','Two','Three','Four','Five','Six','Seven','Eight','Nine','Ten','Eleven','Twelve','Thirteen','Fourteen','Fifteen','Sixteen','Seventeen','Eighteen','Nineteen',]
+    const dict2 = ['','','Twenty','Thirty','Forty','Fifty','Sixty','Seventy','Eighty','Ninety',]
+    let ans = ''
+
+    if (x <= 19) ans = dict1[x] ?? ''
+    else if (x < 100) ans = `${dict2[Math.floor(x / 10)]} ${f(x % 10)}`
+    else if (x < 10 ** 3) ans = `${dict1[Math.floor(x / 100)]} Hundred ${f(x % 100)}`
+    else if (x < 10 ** 6) ans = `${f(Math.floor(x / 10 ** 3))} Thousand ${f(x % 10 ** 3)}`
+    else if (x < 10 ** 9) ans = `${f(Math.floor(x / 10 ** 6))} Million ${f(x % 10 ** 6)}`
+    else ans = `${f(Math.floor(x / 10 ** 9))} Billion ${f(x % 10 ** 9)}`
+
+    return ans.trim()
+  }
+
+    return f(num);
+}
+```
+
 <!-- tabs:end -->
 
 <!-- solution:end -->

solution/0200-0299/0273.Integer to English Words/Solution.js

@@ -0,0 +1,21 @@
+function numberToWords(num) {
+    if (num === 0) return 'Zero';
+
+    // prettier-ignore
+    const f = (x) => {
+    const dict1 = ['','One','Two','Three','Four','Five','Six','Seven','Eight','Nine','Ten','Eleven','Twelve','Thirteen','Fourteen','Fifteen','Sixteen','Seventeen','Eighteen','Nineteen',]
+    const dict2 = ['','','Twenty','Thirty','Forty','Fifty','Sixty','Seventy','Eighty','Ninety',]
+    let ans = ''
+
+    if (x <= 19) ans = dict1[x] ?? ''
+    else if (x < 100) ans = `${dict2[Math.floor(x / 10)]} ${f(x % 10)}`
+    else if (x < 10 ** 3) ans = `${dict1[Math.floor(x / 100)]} Hundred ${f(x % 100)}`
+    else if (x < 10 ** 6) ans = `${f(Math.floor(x / 10 ** 3))} Thousand ${f(x % 10 ** 3)}`
+    else if (x < 10 ** 9) ans = `${f(Math.floor(x / 10 ** 6))} Million ${f(x % 10 ** 6)}`
+    else ans = `${f(Math.floor(x / 10 ** 9))} Billion ${f(x % 10 ** 9)}`
+
+    return ans.trim()
+  }
+
+    return f(num);
+}