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LC 2601. Prime Subtraction Operation (Rust)
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README.md

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| [2543. Check if Point Is Reachable][lc2543] | 🔴 Hard | [![python](res/py.png)][lc2543py] [![rust](res/rs.png)][lc2543rs] |
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| [2583. Kth Largest Sum in a Binary Tree][lc2583] | 🟠 Medium | [![rust](res/rs.png)][lc2583rs] |
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| [2585. Number of Ways to Earn Points][lc2585] | 🔴 Hard | [![python](res/py.png)][lc2585py] [![rust](res/rs.png)][lc2585rs] |
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| [2601. Prime Subtraction Operation][lc2601] | 🟠 Medium | [![rust](res/rs.png)][lc2601rs] |
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| [2616. Minimize the Maximum Difference of Pairs][lc2616] | 🟠 Medium | [![rust](res/rs.png)][lc2616rs] |
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| [2618. Check if Object Instance of Class][lc2618] | 🟠 Medium | [![js](res/js.png)][lc2618js] |
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| [2619. Array Prototype Last][lc2619] | 🟢 Easy | [![js](res/js.png)][lc2619js] |
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[lc2585]: https://leetcode.com/problems/number-of-ways-to-earn-points/
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[lc2585py]: leetcode/number-of-ways-to-earn-points.py
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[lc2585rs]: leetcode/number-of-ways-to-earn-points.rs
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[lc2601]: https://leetcode.com/problems/prime-subtraction-operation/
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[lc2601rs]: leetcode/prime-subtraction-operation.rs
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[lc2616]: https://leetcode.com/problems/minimize-the-maximum-difference-of-pairs/
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[lc2616rs]: leetcode/minimize-the-maximum-difference-of-pairs.rs
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[lc2618]: https://leetcode.com/problems/check-if-object-instance-of-class/
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// 2601. Prime Subtraction Operation
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// 🟠 Medium
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//
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// https://leetcode.com/problems/prime-subtraction-operation/
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//
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// Tags: Array - Math - Binary Search - Greedy - Number Theory
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struct Solution;
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impl Solution {
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/// Iterate over the values from right to left, for each value, we try to find a prime we can
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/// subtract that makes the value less than the one to the right but still greater than 0.
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///
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/// Time complexity: O(n) - We iterate over all the values in the input, for each, we try to
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/// find a prime number we can subtract iterating over a fixed number of elements.
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/// Space complexity: O(1) - Constant extra memory used.
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///
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/// Runtime 0 ms Beats 100%
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/// Memory 2.14 MB Beats 100%
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pub fn prime_sub_operation(nums: Vec<i32>) -> bool {
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fn doit(state: i32, x: i32) -> Option<i32> {
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let primes = [
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0, 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73,
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79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163,
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167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251,
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257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349,
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353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443,
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449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557,
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563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647,
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653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757,
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761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863,
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877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983,
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991, 997,
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];
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// State is the value to the right.
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for val in primes.into_iter().map(|prime| x - prime) {
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if val < state && val > 0 {
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return Some(val);
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}
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}
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None
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}
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nums.into_iter().rev().try_fold(i32::MAX, doit).is_some()
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}
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}
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// Tests.
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fn main() {
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let tests = [
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(vec![4, 9, 6, 10], true),
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(vec![6, 8, 11, 12], true),
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(vec![5, 8, 3], false),
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];
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println!("\n\x1b[92m» Running {} tests...\x1b[0m", tests.len());
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let mut success = 0;
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for (i, t) in tests.iter().enumerate() {
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let res = Solution::prime_sub_operation(t.0.clone());
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if res == t.1 {
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success += 1;
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println!("\x1b[92m✔\x1b[95m Test {} passed!\x1b[0m", i);
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} else {
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println!(
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"\x1b[31mx\x1b[95m Test {} failed expected: {:?} but got {}!!\x1b[0m",
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i, t.1, res
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);
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}
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}
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println!();
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if success == tests.len() {
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println!("\x1b[30;42m✔ All tests passed!\x1b[0m")
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} else if success == 0 {
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println!("\x1b[31mx \x1b[41;37mAll tests failed!\x1b[0m")
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} else {
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println!(
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"\x1b[31mx\x1b[95m {} tests failed!\x1b[0m",
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tests.len() - success
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)
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}
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}

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