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docs/sql/SQL-joins/self-join.md

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---
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id: self-join
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title: SQL SELF JOIN #Remember to keep this unique, as it maps with giscus discussions in the recodehive/support/general discussions
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sidebar_label: SELF JOIN #displays in sidebar
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sidebar_position: 7
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tags:
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[
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sql,
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self join,
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sql self join,
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hierarchical data,
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recursive queries,
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join tables,
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relational database,
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sql tutorial,
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database queries,
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]
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description: Learn about SQL SELF JOIN, how to join a table with itself, syntax, examples, and use cases for hierarchical data and comparing rows within the same table.
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---
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##
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SQL **SELF JOIN** is a technique where a table is joined with itself to compare rows within the same table or to work with hierarchical data structures. This is accomplished by treating the same table as if it were two separate tables using different table aliases.
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:::note
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Key Characteristics of SELF JOIN:
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**Same Table**: Joins a table with itself using different aliases.
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**Hierarchical Data**: Perfect for parent-child relationships within a single table.
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**Row Comparison**: Enables comparison between different rows in the same table.
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**Flexible Join Types**: Can be INNER, LEFT, RIGHT, or FULL OUTER self joins.
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:::
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<BrowserWindow url="https://github.com" bodyStyle={{padding: 0}}>
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[![GitHub](./assets/self-join.png)](https://github.com/sanjay-kv)
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</BrowserWindow>
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:::success
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**When to Use SELF JOIN:**
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**Hierarchical Structures**: Employee-manager relationships, organizational charts
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**Comparing Rows**: Finding duplicates, comparing values within the same table
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**Sequential Data**: Analyzing consecutive records or time-series data
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**Graph Relationships**: Social networks, recommendation systems
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**Parent-Child Data**: Category trees, menu structures, geographical hierarchies
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**Real-World Example:**
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An employee table where each employee has a manager_id pointing to another employee in the same table. SELF JOIN helps you retrieve employee names along with their manager names.
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:::
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:::info
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## Basic SELF JOIN Syntax
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```sql
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SELECT columns
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FROM table_name alias1
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JOIN table_name alias2
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ON alias1.column = alias2.column;
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```
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| **Component** | **Purpose** | **Example** |
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|---------------|-------------|-------------|
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| SELECT | Choose columns from both aliases | `SELECT e1.name, e2.name AS manager` |
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| FROM | First reference to table | `FROM employees e1` |
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| JOIN | Second reference to same table | `JOIN employees e2` |
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| ON | Join condition | `ON e1.manager_id = e2.employee_id` |
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## Table Alias Requirements
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```sql
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-- Wrong: No aliases (causes ambiguity)
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SELECT name, name
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FROM employees
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JOIN employees ON manager_id = employee_id;
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-- Correct: Using aliases to distinguish references
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SELECT e1.name AS employee, e2.name AS manager
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FROM employees e1
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JOIN employees e2 ON e1.manager_id = e2.employee_id;
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```
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:::
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## Practical Examples
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<Tabs>
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<TabItem value="Employee Manager Hierarchy">
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```sql
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-- Get employees and their managers
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SELECT
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e1.employee_id,
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e1.employee_name AS employee,
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e1.position AS employee_position,
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e1.salary AS employee_salary,
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e2.employee_id AS manager_id,
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e2.employee_name AS manager,
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e2.position AS manager_position,
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e1.hire_date,
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DATEDIFF(CURRENT_DATE, e1.hire_date) AS days_employed
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FROM employees e1
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LEFT JOIN employees e2 ON e1.manager_id = e2.employee_id
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WHERE e1.status = 'Active'
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ORDER BY e2.employee_name, e1.employee_name;
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-- LEFT JOIN ensures we see employees without managers (CEO, etc.)
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```
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</TabItem>
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<TabItem value="Find Duplicates">
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```sql
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-- Find duplicate customer records based on email
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SELECT
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c1.customer_id AS customer1_id,
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c1.customer_name AS customer1_name,
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c1.email,
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c1.registration_date AS reg_date1,
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c2.customer_id AS customer2_id,
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c2.customer_name AS customer2_name,
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c2.registration_date AS reg_date2,
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ABS(DATEDIFF(c1.registration_date, c2.registration_date)) AS days_apart
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FROM customers c1
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INNER JOIN customers c2
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ON c1.email = c2.email
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AND c1.customer_id < c2.customer_id -- Avoid duplicate pairs
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WHERE c1.email IS NOT NULL
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AND c1.email != ''
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ORDER BY c1.email, c1.registration_date;
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```
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</TabItem>
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<TabItem value="Sequential Data Analysis">
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```sql
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-- Compare consecutive sales records to find trends
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SELECT
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s1.sale_date AS current_date,
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s1.daily_sales AS current_sales,
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s2.sale_date AS previous_date,
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s2.daily_sales AS previous_sales,
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(s1.daily_sales - s2.daily_sales) AS sales_change,
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ROUND(((s1.daily_sales - s2.daily_sales) / s2.daily_sales) * 100, 2) AS percent_change,
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CASE
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WHEN s1.daily_sales > s2.daily_sales THEN 'Increase'
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WHEN s1.daily_sales < s2.daily_sales THEN 'Decrease'
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ELSE 'No Change'
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END AS trend
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FROM daily_sales s1
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INNER JOIN daily_sales s2
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ON s1.sale_date = DATE_ADD(s2.sale_date, INTERVAL 1 DAY)
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WHERE s1.sale_date >= '2024-01-02' -- Skip first date (no previous)
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ORDER BY s1.sale_date;
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```
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</TabItem>
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<TabItem value="Product Recommendations">
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```sql
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-- Find products frequently bought together
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SELECT
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p1.product_name AS product1,
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p2.product_name AS product2,
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COUNT(*) AS times_bought_together,
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AVG(oi1.unit_price) AS avg_price_product1,
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AVG(oi2.unit_price) AS avg_price_product2,
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COUNT(DISTINCT oi1.order_id) AS total_orders
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FROM order_items oi1
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INNER JOIN order_items oi2
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ON oi1.order_id = oi2.order_id
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AND oi1.product_id < oi2.product_id -- Avoid duplicate pairs
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INNER JOIN products p1 ON oi1.product_id = p1.product_id
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INNER JOIN products p2 ON oi2.product_id = p2.product_id
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WHERE oi1.product_id != oi2.product_id
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GROUP BY oi1.product_id, oi2.product_id, p1.product_name, p2.product_name
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HAVING COUNT(*) >= 5 -- At least 5 co-purchases
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ORDER BY times_bought_together DESC, p1.product_name;
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```
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</TabItem>
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<TabItem value="Geographic Hierarchy">
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```sql
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-- Create location hierarchy (Country -> State -> City)
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SELECT
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city.location_name AS city,
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city.population AS city_population,
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state.location_name AS state,
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country.location_name AS country,
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country.population AS country_population,
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CONCAT(city.location_name, ', ', state.location_name, ', ', country.location_name) AS full_address
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FROM locations city
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LEFT JOIN locations state ON city.parent_location_id = state.location_id
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LEFT JOIN locations country ON state.parent_location_id = country.location_id
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WHERE city.location_type = 'City'
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AND city.active = 1
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ORDER BY country.location_name, state.location_name, city.location_name;
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```
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</TabItem>
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<TabItem value="Sample Output">
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```plaintext
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-- Sample result for employee-manager relationship:
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employee_id | employee | employee_position | manager_id | manager | manager_position
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------------|---------------|-------------------|------------|---------------|------------------
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101 | Alice Johnson | Software Engineer | 201 | Bob Smith | Engineering Manager
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102 | Carol Davis | Software Engineer | 201 | Bob Smith | Engineering Manager
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103 | David Wilson | QA Tester | 202 | Eve Brown | QA Manager
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201 | Bob Smith | Engineering Mgr | 301 | Frank Taylor | VP Engineering
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202 | Eve Brown | QA Manager | 301 | Frank Taylor | VP Engineering
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301 | Frank Taylor | VP Engineering | NULL | NULL | NULL
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-- Note: Frank Taylor has NULL manager (top of hierarchy)
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-- Multiple employees can report to the same manager
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```
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</TabItem>
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</Tabs>
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## Performance Considerations
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:::tip
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**SELF JOIN Performance Tips:**
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1. **Proper Indexing**: Ensure columns used in join conditions are indexed
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```sql
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-- Essential indexes for employee hierarchy
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CREATE INDEX idx_employees_manager_id ON employees(manager_id);
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CREATE INDEX idx_employees_employee_id ON employees(employee_id);
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```
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2. **Limit Recursive Depth**: Prevent infinite loops in hierarchical queries
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```sql
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-- Add level limit to recursive queries
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WHERE level <= 5 -- Maximum 5 levels deep
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```
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3. **Filter Early**: Use WHERE clauses to reduce dataset size
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```sql
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-- Filter before joining for better performance
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FROM employees e1
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JOIN employees e2 ON e1.manager_id = e2.employee_id
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WHERE e1.status = 'Active' AND e2.status = 'Active';
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```
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4. **Use EXISTS for Existence Checks**:
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```sql
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-- More efficient for checking if employee has subordinates
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SELECT employee_name,
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EXISTS(SELECT 1 FROM employees e2 WHERE e2.manager_id = e1.employee_id) AS is_manager
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FROM employees e1;
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```
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5. **Avoid Cartesian Products**:
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```sql
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-- Bad: Missing join condition creates Cartesian product
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SELECT e1.name, e2.name FROM employees e1, employees e2;
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-- Good: Proper join condition
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SELECT e1.name, e2.name
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FROM employees e1
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JOIN employees e2 ON e1.manager_id = e2.employee_id;
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```
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:::
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## Best Practices Summary
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:::info
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**SELF JOIN Best Practices:**
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**✅ Essential Guidelines:**
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1. **Always Use Table Aliases**: Required to distinguish table references
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2. **Proper Join Conditions**: Ensure meaningful relationships between rows
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3. **Handle NULLs Appropriately**: Use LEFT JOIN for optional relationships
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4. **Index Join Columns**: Critical for performance with large tables
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5. **Limit Result Sets**: Use WHERE clauses and LIMIT when testing
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6. **Document Complex Logic**: Comment hierarchical and recursive queries
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7. **Test Edge Cases**: Verify behavior with NULL values and missing relationships
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**🔧 Performance Optimization:**
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```sql
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-- Example of well-optimized SELF JOIN
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SELECT
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emp.employee_name AS employee,
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mgr.employee_name AS manager,
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emp.department
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FROM employees emp
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LEFT JOIN employees mgr ON emp.manager_id = mgr.employee_id
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WHERE emp.status = 'Active' -- Filter early
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AND emp.hire_date >= '2020-01-01' -- Limit scope
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AND (mgr.status = 'Active' OR mgr.status IS NULL) -- Handle NULLs
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ORDER BY emp.department, mgr.employee_name, emp.employee_name
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LIMIT 1000; -- Reasonable limit for testing
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```
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**📝 Documentation Example:**
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```sql
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/*
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Purpose: Generate employee hierarchy report showing direct reporting relationships
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Business Logic:
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- Shows all active employees and their direct managers
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- Includes employees without managers (CEO level)
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- Orders by department then hierarchy
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Performance: Uses indexes on employee_id and manager_id columns
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*/
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```
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:::
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## Conclusion
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SELF JOIN is a powerful technique for analyzing relationships within a single table. Whether you're working with hierarchical organizational data, comparing sequential records, finding duplicates, or analyzing peer relationships, mastering SELF JOIN will significantly enhance your ability to extract meaningful insights from your data. Remember to always use proper aliases, handle NULL values appropriately, and optimize for performance with appropriate indexing and filtering.
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<GiscusComments/>

sidebars.ts

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@@ -123,7 +123,8 @@ const sidebars: SidebarsConfig = {
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'sql/SQL-joins/left-join',
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'sql/SQL-joins/right-join',
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'sql/SQL-joins/full-outer-join',
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'sql/SQL-joins/cross-join'
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'sql/SQL-joins/cross-join',
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'sql/SQL-joins/self-join',
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],
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},
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],

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