ExportCommand.cs now passes the file name when exporting

Kristupasc · Kristupasc · commit 590a5345a65a · 2025-03-26T17:32:51.000+01:00
diff --git a/Rubberduck.Core/UI/CodeExplorer/Commands/ExportCommand.cs b/Rubberduck.Core/UI/CodeExplorer/Commands/ExportCommand.cs
@@ -101,7 +101,8 @@ public bool PromptFileNameAndExport(QualifiedModuleName qualifiedModule)
                 var component = ProjectsProvider.Component(qualifiedModule);
                 try
                 {
-                    var path = Path.GetDirectoryName(dialog.FileName);
+                    //var path = Path.GetDirectoryName(dialog.FileName);
+                    var path = dialog.FileName; // This makes it that the file is named not as the module name, but as the file name the user provided in the explorer.
                     component.ExportAsSourceFile(path, false, true); // skipped optional parameters interfere with mock setup
                 }
                 catch (Exception ex)

Original file line number	Diff line number	Diff line change
`@@ -101,7 +101,8 @@ public bool PromptFileNameAndExport(QualifiedModuleName qualifiedModule)`
`101`	`101`	`var component = ProjectsProvider.Component(qualifiedModule);`
`102`	`102`	`try`
`103`	`103`	`{`
`104`		`- var path = Path.GetDirectoryName(dialog.FileName);`
	`104`	`+ //var path = Path.GetDirectoryName(dialog.FileName);`
	`105`	`+ var path = dialog.FileName; // This makes it that the file is named not as the module name, but as the file name the user provided in the explorer.`
`105`	`106`	`component.ExportAsSourceFile(path, false, true); // skipped optional parameters interfere with mock setup`
`106`	`107`	`}`
`107`	`108`	`catch (Exception ex)`