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Fix typo and formatting
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keps/sig-scheduling/5142-pop-backoffq-when-activeq-empty/README.md

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@@ -168,7 +168,7 @@ and the backoff time is calculated based on the number of scheduling failures th
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If one pod has a smaller attempt counter than others,
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could the scheduler keep popping this pod ahead of other pods because the pod's backoff expires faster than others?
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Actually, that wouldn't happen because the scheduler would increment the attempt counter of pods from the backoffQ as well,
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which would make the backoff time larger after each after the scheduling attempt,
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which would make the backoff time larger after each scheduling attempt,
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and the pod that had a smaller attempt number eventually won't be popped out.
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### Low priority pod could be chosen to pop, even if high priority pod has a slightly later backoff expiration

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