Revert loose number parsing to pre-1.2.0 state. (#24)

* Revert loose number parsing to pre-1.2.0 state.

When the loose option is "true", numbers with operators will now be parsed the same way as in 1.1.0.

* Fix test failure

Could've sworn I tested that locally

Author: jwilsson

lib/parser.js

@@ -169,9 +169,15 @@ module.exports = class Parser {
         }
       }
 
-      // if ((!this.current.nodes.length || (this.current.last && this.current.last.type === 'operator')) && this.nextToken[0] === 'word') {
-      if (this.nextToken[0] === 'word') {
-        return this.word();
+      if (!this.options.loose) {
+        if (this.nextToken[0] === 'word') {
+          return this.word();
+        }
+      }
+      else {
+        if ((!this.current.nodes.length || (this.current.last && this.current.last.type === 'operator')) && this.nextToken[0] === 'word') {
+          return this.word();
+        }
       }
     }
 

test/number.js

@@ -153,15 +153,15 @@ describe('Parser → Number : Loose', () => {
     },
     {
       test: '5+5',
-      expected: { value: '+5', unit: '', length: 2 }
+      expected: { value: '5', unit: '', length: 3 }
     },
     {
       test: '5+-+-+-+5',
       expected: { value: '+5', unit: '', length: 8 }
     },
     {
-      test: '-16px -1px -1px -16px',
-      expected: { value: '-16', unit: 'px', length: 4 }
+      test: '-16px -1px -1px 16px',
+      expected: { value: '16', unit: 'px', length: 6 }
     }
   ];