changes updated

Author: AbhijitRaut04

lib/node_modules/@stdlib/math/base/special/minmax/benchmark/c/native/benchmark.c

@@ -93,7 +93,7 @@ static double benchmark( void ) {
 	double elapsed;
 	double x1[100];
 	double x2[100];
-	double* y = ( double* )malloc(2 * sizeof(double));
+	double y[] = { 0.0, 0.0 };
 	double t;
 	int i;
 
@@ -104,7 +104,7 @@ static double benchmark( void ) {
 
 	t = tic();
 	for ( i = 0; i < ITERATIONS; i++ ) {
-		y = stdlib_base_minmax( x1[ i % 100 ], x2[ i % 100 ] );
+		stdlib_base_minmax( x1[ i % 100 ], x2[ i % 100 ], &y, 1, 0 );
 		if ( y != y ) {
 			printf( "should not return NaN\n" );
 			break;

lib/node_modules/@stdlib/math/base/special/minmax/examples/c/example.c

@@ -24,11 +24,11 @@ int main(void) {
     const double x1[] = { 1.0, 0.45, -0.89, 0.0 / 0.0, -0.78, -0.22, 0.66, 0.11, -0.55, 0.0 };
 	const double x2[] = { -0.22, 0.66, 0.0, -0.55, 0.33, 1.0, 0.0 / 0.0, 0.11, 0.45, -0.78 };
 
-	double* v = ( double* )malloc(2 * sizeof(double));
 	int i;
 	for ( i = 0; i < 10; i++ ) {
-		v = stdlib_base_minmax( x1[ i ], x2[ i ] );
-		printf( "x1[ %d ]: %lf, x2[ %d ]: %lf, minmax( x1[ %d ], x2[ %d ] ): ( %lf, %lf )\n", i, x1[ i ], i, x2[ i ], i, i, v[0], v[1] );
+		double out[] = { 0.0, 0.0 };
+		stdlib_base_minmax( x1[ i ], x2[ i ], &out, 1, 0 );
+		printf( "x1[ %d ]: %lf, x2[ %d ]: %lf, minmax( x1[ %d ], x2[ %d ] ): ( %lf, %lf )\n", i, x1[ i ], i, x2[ i ], i, i, out[0], out[1] );
 	}
 }
 

lib/node_modules/@stdlib/math/base/special/minmax/include/stdlib/math/base/special/minmax.h

@@ -37,7 +37,7 @@ extern "C" {
 * @param y   Second value
 * @return    A double containing the minimum and maximum values
 */
-double* stdlib_base_minmax(const double x, const double y, double* out, int stride, int offset );
+void stdlib_base_minmax(const double x, const double y, double* out, int stride, int offset );
 
 #ifdef __cplusplus
 }

lib/node_modules/@stdlib/math/base/special/minmax/src/main.c

@@ -35,7 +35,7 @@
 */
 
 
-double* stdlib_base_minmax( const double x, const double y, double* out, int stride, int offset ) {
+void stdlib_base_minmax( const double x, const double y, double* out, int stride, int offset ) {
 
     if( stdlib_base_is_nan( x ) || stdlib_base_is_nan( y ) ){
         out[ offset ] = 0.0 / 0.0;
@@ -46,6 +46,6 @@ double* stdlib_base_minmax( const double x, const double y, double* out, int str
         out[ offset + stride ] = stdlib_base_max( x, y );
     }
 
-    return out; 
+    return; 
 
 }