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</head><body><i class="fa fa-arrow-right" id="toggle-sidebar" aria-hidden="true"></i><div id="sidebar" data-display="false"><div class="author-info"><div class="author-info__avatar text-center"><img src="https://su1yu4n.github.io/images/avatar_miku.png"></div><div class="author-info__name text-center">随缘(su1yu4n)</div><div class="author-info__description text-center">Nepnep棺材板，XDSEC潜水员，CTF纯业余。发一些数学密码学和技术相关的内容，以及个人相关的内容。</div><hr><div class="author-info-articles"><a class="author-info-articles__archives article-meta" href="/archives"><span class="pull-left">文章</span><span class="pull-right">20</span></a><a class="author-info-articles__tags article-meta" href="/tags"><span class="pull-left">标签</span><span class="pull-right">29</span></a><a class="author-info-articles__categories article-meta" href="/categories"><span class="pull-left">分类</span><span class="pull-right">4</span></a></div><hr><div class="author-info-links"><div class="author-info-links__title text-center">Friends</div><a 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fas"></i></a><a class="social-icon" href="mailto:su1yu4n@gmail.com" target="_blank" rel="noreferrer noopener nofollow"><i class="fa-envelope fas"></i></a></div></div></nav><div id="content-outer"><div class="layout" id="content-inner"><div class="recent-post-item article-container"><a class="article-title" href="/2025/08/01/NepCTF2025-ezRSA2%E5%AE%98%E6%96%B9%E9%A2%98%E8%A7%A3/">NepCTF2025 ezRSA2官方题解</a><time class="post-meta__date"><i class="fa fa-calendar" aria-hidden="true"></i> 2025-08-01</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Cryptology/">Cryptology</a></span><span class="article-meta tags"><span class="article-meta__separator">|</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/CTF/">CTF</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/RSA/">RSA</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/%E5%AF%86%E7%A0%81%E5%88%86%E6%9E%90/">密码分析</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/Coppersmith/">Coppersmith</a></span><div class="content"><p>这是一个简单的RSA二元Coppersmith。题目中已知$d < N^{0.33}$, 以及一些$d \bmod l_i$的值。这些$l_i$的乘积约为$N^{0.17}$。</p>
<p>这道题也可以用Wiener攻击的思路构造三维格求解。以下为题目和两种解法的详细说明。</p></div><a class="more" href="/2025/08/01/NepCTF2025-ezRSA2%E5%AE%98%E6%96%B9%E9%A2%98%E8%A7%A3/#more">阅读更多</a><hr></div><div class="recent-post-item article-container"><a class="article-title" href="/2024/10/15/CSIDH%E6%96%B9%E6%A1%88%E5%88%86%E4%BA%AB/">CSIDH方案短课（沙龙）</a><time class="post-meta__date"><i class="fa fa-calendar" aria-hidden="true"></i> 2024-10-15</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Cryptology/">Cryptology</a></span><span class="article-meta tags"><span class="article-meta__separator">|</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/isogeny/">isogeny</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/CSIDH/">CSIDH</a></span><div class="content"><p>这段时间研究CSIDH，时间跨度接近一年了。<strong>这次分享尽可能降低了门槛，让大家听懂。</strong></p>
<p>个人认为CSIDH方案是数学、计算优化与工科思维的集大成者。同源密码用到的数学比较深，而同源计算也很灵活，可以将群论与工科式的想法结合。<strong>这次分享对数学原理和优化都有所覆盖。</strong></p>
<p>CM Torsor的性质没有深入，想了解建议看复环面/复椭圆曲线的复乘理论。</p></div><a class="more" href="/2024/10/15/CSIDH%E6%96%B9%E6%A1%88%E5%88%86%E4%BA%AB/#more">阅读更多</a><hr></div><div class="recent-post-item article-container"><a class="article-title" href="/2024/04/30/Solution-to-S0DH/">Solution to S0DH in D3CTF 2024</a><time class="post-meta__date"><i class="fa fa-calendar" aria-hidden="true"></i> 2024-04-30</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Cryptology/">Cryptology</a></span><span class="article-meta tags"><span class="article-meta__separator">|</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/CTF/">CTF</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/isogeny/">isogeny</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/SIDH/">SIDH</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/MITM/">MITM</a></span><div class="content"><p>Here’s the official writeup for S0DH, including the challenge and solutions (intended and unintended).<br></div><a class="more" href="/2024/04/30/Solution-to-S0DH/#more">阅读更多</a><hr></div><div class="recent-post-item article-container"><a class="article-title" href="/2023/11/03/LadderLeak%E8%AE%BA%E6%96%87%E5%88%86%E4%BA%AB/">LadderLeak论文分享</a><time class="post-meta__date"><i class="fa fa-calendar" aria-hidden="true"></i> 2023-11-03</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Cryptology/">Cryptology</a></span><span class="article-meta tags"><span class="article-meta__separator">|</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/%E5%AF%86%E7%A0%81%E5%88%86%E6%9E%90/">密码分析</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/%E4%BE%A7%E4%BF%A1%E9%81%93%E6%94%BB%E5%87%BB/">侧信道攻击</a></span><div class="content"><p>去年讲了论文：<a target="_blank" rel="noopener" href="https://eprint.iacr.org/2020/615">LadderLeak: Breaking ECDSA With Less Than One Bit Of Nonce Leakage</a>，<strong>现在公开幻灯片，请点击阅读更多获取</strong>。</p></div><a class="more" href="/2023/11/03/LadderLeak%E8%AE%BA%E6%96%87%E5%88%86%E4%BA%AB/#more">阅读更多</a><hr></div><div class="recent-post-item article-container"><a class="article-title" href="/2023/09/05/%E5%A4%8D%E5%8F%98%E5%87%BD%E6%95%B0%E7%AC%94%E8%AE%B0/">复变函数笔记</a><time class="post-meta__date"><i class="fa fa-calendar" aria-hidden="true"></i> 2023-09-05</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Math/">Math</a></span><span class="article-meta tags"><span class="article-meta__separator">|</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/%E5%A4%8D%E5%88%86%E6%9E%90/">复分析</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/%E5%AD%A6%E4%B9%A0%E7%AC%94%E8%AE%B0/">学习笔记</a></span><div class="content"><p>（9.21更新， 不过当时部署之后没更新显示…）</p>
<p>学习了史济怀的《复变函数》第2~4章。第五章没细看，因为个人需求是会洛朗展开和留数定理去计算就行，而这两个东西早就知道了，因此就看了Borcherds的课，跟着用草稿纸去算一算特定的积分。</p>
<p>笔记有很多习题空着了，部分内容也跳过了。不过确实是写了自己思考的一些东西… 也许有一天再用复分析的时候干脆讲一讲，再完善一下这些笔记。还有二次剩余分布问题也可以讲一讲。</p></div><a class="more" href="/2023/09/05/%E5%A4%8D%E5%8F%98%E5%87%BD%E6%95%B0%E7%AC%94%E8%AE%B0/#more">阅读更多</a><hr></div><div class="recent-post-item article-container"><a class="article-title" href="/2023/04/17/%E5%AF%86%E7%A0%81%E5%AD%A6%E4%B8%AD%E7%9A%84%E6%A4%AD%E5%9C%86%E6%9B%B2%E7%BA%BF%E7%9F%A5%E8%AF%86/">知识分享会：密码学中的椭圆曲线</a><time class="post-meta__date"><i class="fa fa-calendar" aria-hidden="true"></i> 2023-04-17</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Math/">Math</a></span><span class="article-meta tags"><span class="article-meta__separator">|</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/Elliptic-Curves/">Elliptic Curves</a></span><div class="content"><p><strong>(2023.4) 计划增加一些新内容（但可能没时间了…）</strong></p>
<p>椭圆曲线密码学实际上涉及到不少高深的数学知识。2022年10月在Nepnep战队做了一次线上分享，听众还有其他对密码学感兴趣的朋友以及geek学院的朋友等。<strong>主要内容是代数学基础回顾、射影几何基础以及GTM 106前三章的部分内容</strong>。</p></div><a class="more" href="/2023/04/17/%E5%AF%86%E7%A0%81%E5%AD%A6%E4%B8%AD%E7%9A%84%E6%A4%AD%E5%9C%86%E6%9B%B2%E7%BA%BF%E7%9F%A5%E8%AF%86/#more">阅读更多</a><hr></div><div class="recent-post-item article-container"><a class="article-title" href="/2023/02/23/COA_RSA%E9%A2%98%E7%9B%AE%E7%BB%86%E8%8A%82%E5%8F%8A%E5%8F%8D%E6%80%9D/">NepCTF2022 - COA_RSA解读</a><time class="post-meta__date"><i class="fa fa-calendar" aria-hidden="true"></i> 2023-02-23</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Cryptology/">Cryptology</a></span><span class="article-meta tags"><span class="article-meta__separator">|</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/CTF/">CTF</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/%E5%87%BA%E9%A2%98%E8%AE%B0%E5%BD%95/">出题记录</a></span><div class="content"><p>之前给NepCTF 2022出了几道密码题，其中就包括这道… 官方题解WP在<a target="_blank" rel="noopener" href="https://www.wolai.com/nepnep/q8dyRhz2ufGtqWTqnyeUwv">这里</a>。当时是想出一道反论文题，不过赛后发现做出来的选手中很多还是看论文做的。<strong>题目对应的论文本身写得很差，不推荐阅读。</strong></p>
<p>后来跟shallow师傅讨论了一下，又看了下<strong>当时的WP发现有很多细节没说，并且有点小问题。因此现在补充一下。</strong></p></div><a class="more" href="/2023/02/23/COA_RSA%E9%A2%98%E7%9B%AE%E7%BB%86%E8%8A%82%E5%8F%8A%E5%8F%8D%E6%80%9D/#more">阅读更多</a><hr></div><div class="recent-post-item article-container"><a class="article-title" href="/2023/02/23/%E5%90%8C%E6%80%81%E5%8A%A0%E5%AF%86%EF%BC%9APaillier%E6%96%B9%E6%A1%88%E5%AD%A6%E4%B9%A0/">同态加密：Paillier方案学习</a><time class="post-meta__date"><i class="fa fa-calendar" aria-hidden="true"></i> 2023-02-23</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Cryptology/">Cryptology</a></span><span class="article-meta tags"><span class="article-meta__separator">|</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/%E5%90%8C%E6%80%81%E5%8A%A0%E5%AF%86/">同态加密</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/%E5%8D%8A%E5%90%8C%E6%80%81%E5%8A%A0%E5%AF%86%EF%BC%88PHE%EF%BC%89/">半同态加密（PHE）</a></span><div class="content"><p>本文总结Paillier及其变种Paillier-DJN方案。</p></div><a class="more" href="/2023/02/23/%E5%90%8C%E6%80%81%E5%8A%A0%E5%AF%86%EF%BC%9APaillier%E6%96%B9%E6%A1%88%E5%AD%A6%E4%B9%A0/#more">阅读更多</a><hr></div><div class="recent-post-item article-container"><a class="article-title" href="/2023/02/23/CatCTF%E5%87%BA%E9%A2%98%E5%B0%8F%E8%AE%B0/">CatCTF出题小记</a><time class="post-meta__date"><i class="fa fa-calendar" aria-hidden="true"></i> 2023-02-23</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Cryptology/">Cryptology</a></span><span class="article-meta tags"><span class="article-meta__separator">|</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/CTF/">CTF</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/%E5%87%BA%E9%A2%98%E8%AE%B0%E5%BD%95/">出题记录</a></span><div class="content"><p>CatCTF的题目总结以及出题的动机、想法。</p></div><a class="more" href="/2023/02/23/CatCTF%E5%87%BA%E9%A2%98%E5%B0%8F%E8%AE%B0/#more">阅读更多</a><hr></div><div class="recent-post-item article-container"><a class="article-title" href="/2022/11/19/%E5%87%A0%E4%B8%AA%E5%AF%B9CBC%E6%A8%A1%E5%BC%8F%E7%9A%84%E7%AE%80%E5%8D%95%E6%94%BB%E5%87%BB/">几个对CBC模式分组密码的简单攻击</a><time class="post-meta__date"><i class="fa fa-calendar" aria-hidden="true"></i> 2022-11-19</time><span class="article-meta"><span class="article-meta__separator">|</span><i class="fa fa-inbox article-meta__icon" aria-hidden="true"></i><a class="article-meta__categories" href="/categories/Cryptology/">Cryptology</a></span><span class="article-meta tags"><span class="article-meta__separator">|</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/%E5%88%86%E7%BB%84%E5%AF%86%E7%A0%81/">分组密码</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/Padding-Oracle-Attack/">Padding Oracle Attack</a><span class="article-meta__link">-</span><i class="fa fa-tag article-meta__icon" aria-hidden="true"></i><a class="article-meta__tags" href="/tags/%E5%AD%97%E8%8A%82%E7%BF%BB%E8%BD%AC%E6%94%BB%E5%87%BB/">字节翻转攻击</a></span><div class="content"><p><strong>总结CBC模式下的字节翻转攻击和Padding Oracle Attack</strong>。由于时间关系，padding oracle attack的原理部分暂时上传手稿截图。</p></div><a class="more" href="/2022/11/19/%E5%87%A0%E4%B8%AA%E5%AF%B9CBC%E6%A8%A1%E5%BC%8F%E7%9A%84%E7%AE%80%E5%8D%95%E6%94%BB%E5%87%BB/#more">阅读更多</a><hr></div><nav id="pagination"><div class="pagination"><span class="page-number current">1</span><a class="page-number" href="/page/2/">2</a><a class="extend next" rel="next" href="/page/2/"><i class="fa fa-chevron-right"></i></a></div></nav></div></div><footer><div class="layout" id="footer"><div class="copyright">©2022 - 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